循环后我无法选择

Question

def print_menu():
    print('1. American')
    print('2. Asian')
    print('3. Indian')
    print('4. Mexican')
    print('5. French')
    print('6. Italian')
    print('7. Seafood')
    print('8. Pizza')
print_menu()
menu = input('\nChoose where you want to eat from-->')
if menu == "1":
    def american_menu():
        print('1. Dempsey Burger Pub')
        print('2. Redrock Canyon Grill-Wichita')
        print("3. Cheddar's Scratch Kitchen")
        print("4. Neighbors| Restaurant & Bar")
        print("5. The Kitchen")
        print("6. Firebirds Wood Fired Grill")
        print("7. Chicken and Pickle")
    american_menu()
    american = input("\nChoose which American Restaurant--> ")
    if american == "1":
        print("\nCall Dempsey Burger Pub")
        

    while True:
        go_back = input("Will you like to try another menu option?: ")
        if go_back == "Yes":
            print_menu()
        else:
            print("We'll continue with your current choice")
        break

所以我尝试循环播放它，以便它再次从美食中选择并继续前往您想吃的地方，但到目前为止，它只是询问 go_back，在我说是之后......它会再次重复 go_back 任何帮助将不胜感激。谢谢。我希望它循环回到选择，选择我选择的选择和子选择，而不是仅仅选择选择而不做任何事情。再次感谢

注意：这是一项任务，我被卡住了，而且我有一个选择列表，但由于站点原因无法发布。

Answer 1

为print_menu 编写一个while 循环并将continue 更改为break

def print_menu():
    while True:
    #Use 2 while loops if you want. But the loop you are using is not needed  

while True:
    go_back = input("Will you like to try another menu option?: ")
    if go_back == "Yes":
        print_menu()
        break
    else:
        print("We'll continue with your current choice")
        break

第二个选项：

def print_menu():
    while True:
    #Just use "while" here instead of the second one

go_back = input("Will you like to try another menu option?: ")
if go_back == "Yes":
    print_menu()
else:
   print("We'll continue with your current choice")

Answer 2

您根本不需要使用while True 循环。它可能会导致无限循环问题。在用户在 print_menu() 中选择了他的菜单后，您可以通过调用新函数 check_if_wants_to_order_again 来避免它。

def print_menu():
  print('1. American')
  print('2. Asian')
  print('3. Indian')
  print('4. Mexican')
  print('5. French')
  print('6. Italian')
  print('7. Seafood')
  print('8. Pizza')
  menu = input('\nChoose where you want to eat from-->')
  if menu == "1":
    american_menu()
  check_if_wants_to_order_again()

def american_menu():
  print('1. Dempsey Burger Pub')
  print('2. Redrock Canyon Grill-Wichita')
  print("3. Cheddar's Scratch Kitchen")
  print("4. Neighbors| Restaurant & Bar")
  print("5. The Kitchen")
  print("6. Firebirds Wood Fired Grill")
  print("7. Chicken and Pickle")
  american = input("\nChoose which American Restaurant--> ")
  if american == "1":
      print("\nCall Dempsey Burger Pub")

def check_if_wants_to_order_again():
  go_back = input("Will you like to try another menu option? Enter \"Yes\" or \"No\":")
  if go_back == "Yes":
    print_menu()
  else:
    print("We'll continue with your current choice")

print_menu()

Answer 3

当您 continue 循环时，您再次调用 print_menu()，但您没有做任何其他需要遵循 print_menu() 以提示用户做出其他选择的事情。

试一试：

# Define the menus as dictionaries.
# The key is the number that the user will pick,
# the value is the selected item.

# Main menu -- pick a cuisine.
main_menu = {
    "1": "American",
    "2": "Asian",
    "3": "Indian",
    "4": "Mexican",
    "5": "French",
    "6": "Italian",
    "7": "Seafood",
    "8": "Pizza",
}

# American restaurant menu.
american_menu = {
    "1": "Dempsey Burger Pub",
    "2": "Redrock Canyon Grill-Wichita",
    "3": "Cheddar's Scratch Kitchen",
    "4": "Neighbors| Restaurant & Bar",
    "5": "The Kitchen",
    "6": "Firebirds Wood Fired Grill",
    "7": "Chicken and Pickle",
}

# This dict maps each cuisine name to the appropriate submenu.
cuisine_menus = {
    "American": american_menu,
    # "Asian": asian_menu,
    # "French": french_menu,
    # ...
}

# This dict maps each restaurant name to its contact info.
contact_info = {
    "Dempsey Burger Pub": (
        "(316) 425-3831",
        "https://www.dempseysburgerpub.com/"
    ),
    "Redrock Canyon Grill-Wichita": (
        "(316) 636-1844",
        "https://www.redrockcanyongrill.com/"
    ),
    # ...
}

def print_menu(menu):
    """Print a menu, e.g. '1. American'..."""
    for k, v in menu.items():
        print(f"{k}. {v}")

def contact_restaurant(restaurant):
    """Contact a restaurant.  Raises KeyError if we don't have contact info."""
    phone, website = contact_info[restaurant]
    print(restaurant)
    print(f"Phone: {phone}")
    print(f"Website: {website}")
    # maybe do something with website to open a browser?  idk


# Interactive loop.  Go through the menus in turn,
# and repeat when done or when they enter something invalid.
# Break the loop once they finish picking a restaurant.
while True:
    # Main menu (pick a cuisine)
    print_menu(main_menu)
    pick = input('\nChoose where you want to eat from-->')
    # Error checking for invalid picks.
    if pick not in main_menu:
        print("Please select one of the listed options.")
        continue
    cuisine = main_menu[pick]
    if cuisine not in cuisine_menus:
        # This happens if they picked something that was in main_menu
        # but not in cuisine_menus yet because we haven't written that part.
        print("Oops!  Haven't implemented that one yet.")
        print(f"Try {', '.join(cuisine_menus)}")
        continue

    # Now we have a valid main menu pick that we can continue with.
    cuisine_menu = cuisine_menus[cuisine]

    # Print the menu and ask them to pick an item from that.
    print_menu(cuisine_menu)
    pick = input(f"\nChoose which {cuisine} Restaurant--> ")
    if pick not in cuisine_menu:
        print("Sorry, not an option.  Let's start over.")
        continue

    restaurant = cuisine_menu[pick]
    if restaurant not in contact_info:
        print(f"Oops, we don't have contact info for {restaurant}.")
        print("Let's start over...")
        continue
    
    print(f"\nCall {restaurant}")

    # Prompt them to start over.  If they don't, break the loop.
    pick = input("Will you like to try another menu option?: ")
    if pick != "Yes":
        print("We'll continue with your current choice")
        break

# Now the user has picked a restaurant to contact,
# so go ahead and contact them.
contact_restaurant(restaurant)

请注意，所有交互都发生在while True 循环内。每当该循环中有 continue 时，它都会在开始时返回到 print_menu(main_menu)，然后从那里继续。

Answer 4

感谢所有为此做出贡献的人，我终于弄明白了。