每年在R中按日期子集答案

【问题标题】：subset by date in R within each year每年在R中按日期子集
【发布时间】：2022-06-24 00:16:52
【问题描述】：

我的数据如下：

site year date
A    2019 2019-08-08
A    2019 2019-08-18
A    2019 2019-10-14
A    2019 2019-10-27
B    2019 2019-08-07
B    2019 2019-08-19
B    2019 2019-10-15
B    2019 2019-10-20
A    2020 2020-08-08
A    2020 2020-08-18
A    2020 2020-10-14
A    2020 2020-10-27
B    2020 2020-08-07
B    2020 2020-08-19
B    2020 2020-10-15
B    2020 2020-10-20

对于每一年，我想对满足以下条件的行进行子集化：

==8 月 15 日

提前谢谢你！

【问题讨论】：

标签： r

【解决方案1】：

转换为年份并使用filter

library(dplyr)
library(lubridate)
df1 %>% 
  mutate(date = ymd(date)) %>% 
  filter(between(yday(date), 228, 289))

-输出

 site year       date
1    A 2019 2019-08-18
2    A 2019 2019-10-14
3    B 2019 2019-08-19
4    B 2019 2019-10-15
5    A 2020 2020-08-18
6    A 2020 2020-10-14
7    B 2020 2020-08-19
8    B 2020 2020-10-15

数据

df1 <- structure(list(site = c("A", "A", "A", "A", "B", "B", "B", "B", 
"A", "A", "A", "A", "B", "B", "B", "B"), year = c(2019L, 2019L, 
2019L, 2019L, 2019L, 2019L, 2019L, 2019L, 2020L, 2020L, 2020L, 
2020L, 2020L, 2020L, 2020L, 2020L), date = c("2019-08-08", "2019-08-18", 
"2019-10-14", "2019-10-27", "2019-08-07", "2019-08-19", "2019-10-15", 
"2019-10-20", "2020-08-08", "2020-08-18", "2020-10-14", "2020-10-27", 
"2020-08-07", "2020-08-19", "2020-10-15", "2020-10-20")), 
class = "data.frame", row.names = c(NA, 
-16L))

【讨论】：