在字符串c ++中反转单词时输出整个句子

Question

必须创建我们自己的函数来接收来自输入文件的句子/句子。然后它应该单独反转每个单词的字母，并保持明文中的所有其他（非字母）字符不变，即“猫坐在垫子上！”会变成 “ehT tac tas no eht tam！”。 所以我想我找到了一种单独反转单词的方法，但不知道如何找到一种方法在一个句子中输出所有内容。我觉得我需要以某种方式使用数组或向量来帮助存储每个单词，然后最后将所有单词一起输出，但我没有成功。 我还想找到一种方法让它知道何时停止并输出单词之间的空格。

到目前为止，这是我的代码：

#include <iostream>
#include <fstream>
#include <string>
using namespace std; 

void reverse(string input); 

int main(){
    ifstream inData; 
    ofstream outData; 

    string input; 

    inData.open("input.txt"); 
    outData.open("output.txt"); 

    while(getline(inData, input)){
        // cout << input; 
        outData << input; 
    }

   
    reverse(input);

    inData.close(); 
    outData.close(); 
    return 0; 
}

void reverse(string input){
  
    int counter =0;
    while(counter != 14){
    int idx = input.find(" ");
    cout << idx << endl;

    string word = input.substr(0, idx);
    cout << word << endl;
    string x;

    for (int i = idx-1; i >= 0; i--)
    {
        x= word.at(i);
        cout << x; 
    }

    cout << endl;
    input.erase(0,idx+1);

    cout << input << endl;

    cout << endl << "new" << endl;
    
    counter++; 
    }
} 

Answer 1

所以这里的代码可以从输入文件中输出句子，每个单词被反转，然后所有这些单词按照它们在句子中的顺序输出到一个句子中。它还有一些问题，比如如果单词中有一个非字母字符，在前面或结尾之前的某个地方，那个字符会被推到单词的后面，所以这个需要改进。如果有的话，请随意添加建设性的批评。但是，认为这仍然提供了原始问题。谢谢大家的帮助。

#include <fstream>
#include <string>
#include <sstream>
using namespace std; 

void reverse(string input); 

int main(){
    ifstream inData; 
    ofstream outData; 

    string input; 

    inData.open("input.txt"); 
    outData.open("output.txt"); 

    while(getline(inData, input)){          //get sentence from input line
        reverse(input);                     //Reverse the sentence
        cout << endl;                       //end line for next sentence
    }

    inData.close(); 
    outData.close(); 
    return 0; 
}

void reverse(string input){
    string nonAlpha = "";
    bool end = false;
    bool nonLetter = true;

    while(end != true){         
    int idx = input.find(" ");                       //Finds index of blank space
    int lastIdx = input.size();                      //Finds the last index

    if(idx <= 0){                                    //If it is the last index, then that becomes idx
        idx = lastIdx;
        end = true;
    }

    string word = input.substr(0, idx);               //Word usually starts from index 0, until the blank space
    string x;

     
    for (int i = idx-1; i >= 0; i--){                  //Then outputs each letter according to the index of the word 
                                                      // but starts from last index and decrements thereby reversing the word
        if((isalpha(word.at(i))==false)){               //If that index is not a letter then it is stored and will be outputted after word 
           nonAlpha.push_back(word[i]);                 //However this can be a problem for non-letter if not at end of word
           nonLetter = true; 
        }
        else{
        x= word.at(i);
        cout << x;                                      //Prints the letter
        }
        
    }
    
    if(nonLetter == true){
    cout << nonAlpha;                                   //Prints the non-letter
    nonAlpha.erase();                                   //Erases whatever is inside for future non-letters
    nonLetter = false;                                  //Makes it false and will be used agaian when there is another non-letter
    }
    
    cout << " ";                                        //Space between words
    input.erase(0,idx+1);                               //Erases word when finished reversing and outputting it so can start next word

    }

}