为什么休眠删除操作不起作用？

Question

我有一个基本的 Spring MVC 项目，其中包含 User 和 Task 类的经典 dao 设计。我正在为 webapp 使用 Hibernate OpenSessionInView 过滤器模式；但是，我的UserService 工作不正常，实际上是它的删除操作。问题是，我对这个方法有一个简单的单元测试，它似乎工作正常，因为当我运行它时，一切正常，但是当我通过 webapp 测试时，像这样：curl -X DELETE "http://myhost:port/users/someUserId"，删除操作没有完全可以工作，因为对象一旦被调用就会持续存在。

这是我UserService的一部分：

@Override
public <T> User get(String key, T value) {
    User u = new User();

    switch (key) {
    case "id":
        u = (User) session.getCurrentSession().get(User.class, (Serializable) value);
        break;
    case "email":
        u = (User) session.getCurrentSession().createQuery("from User u where u.email = :email").setParameter("email", value.toString()).uniqueResult();
        break;
    case "username":
        u = (User) session.getCurrentSession().createQuery("from User u where u.username = :username").setString("username", (String) value).uniqueResult();
        break;
    }
    if (u != null ) Hibernate.initialize(u.getTasks());
    return u;
}

@Override
public void delete(Integer userId) {
    session.getCurrentSession().delete(get("id",userId));
}

和UserController:

@RequestMapping(value="/{id}", method=RequestMethod.DELETE)
public String deleteMemeber(@PathVariable Integer id) {

    userService.delete(id);

    return "redirect:/";

}

以及UserService 的单元测试删除：

@Test
public void testUserDeleteService() {
    List<User> preUsers = userService.findAll();
    User userToDelete = userService.findById(3);

    userService.delete(3);

    List<User>postUsers = userService.findAll();

    assertNotEquals(preUsers, postUsers);
    assertEquals(preUsers.size() - 1, postUsers.size());
    assertFalse(userService.findAll().contains(userToDelete));
    assertNull(userService.findById(3));
}

关于为什么会发生这种情况的任何想法？

当删除方法被调用时，这是日志记录：

Hibernate: select user0_.id as id1_1_0_, user0_.email as email2_1_0_, user0_.first_name as first_na3_1_0_, user0_.last_name as last_nam4_1_0_, user0_.password as password5_1_0_, user0_.role as role6_1_0_, user0_.enabled as enabled7_1_0_, user0_.username as username8_1_0_ from users user0_ where user0_.id=?
Hibernate: select user0_.id as id1_1_0_, user0_.email as email2_1_0_, user0_.first_name as first_na3_1_0_, user0_.last_name as last_nam4_1_0_, user0_.password as password5_1_0_, user0_.role as role6_1_0_, user0_.enabled as enabled7_1_0_, user0_.username as username8_1_0_ from users user0_ where user0_.id=?
Hibernate: select tasks0_.user_id as user_id6_1_0_, tasks0_.id as id1_0_0_, tasks0_.id as id1_0_1_, tasks0_.created_on as created_2_0_1_, tasks0_.deadline as deadline3_0_1_, tasks0_.description as descript4_0_1_, tasks0_.name as name5_0_1_, tasks0_.user_id as user_id6_0_1_ from tasks tasks0_ where tasks0_.user_id=?

Hibernate: select tasks0_.user_id as user_id6_1_0_, tasks0_.id as id1_0_0_, tasks0_.id as id1_0_1_, tasks0_.created_on as created_2_0_1_, tasks0_.deadline as deadline3_0_1_, tasks0_.description as descript4_0_1_, tasks0_.name as name5_0_1_, tasks0_.user_id as user_id6_0_1_ from tasks   tasks0_ where tasks0_.user_id=?

Answer 1

试试这个删除方法：

@Override
public void delete(Integer userId) {
    session.getCurrentSession().delete(get("id",userId));
    session.getCurrentSession().flush();
}

，也许您只需要刷新活动会话即可查看更改。

Answer 2

您可以更改删除方法并尝试一下吗？

private boolean deleteById(Class<?> type, Serializable id) {
Object persistentInstance = session.load(type, id);
if (persistentInstance != null) {
    session.delete(persistentInstance);
    return true;
}
return false;}

只需调用 deleteById(User.class, id);

是否有任何子类或 1tomany 或 many2many 关联？