两个表的累积余额

Question

我想从 2 个按日期排序的表中获取数据： 获取客户的累计余额

我想从中获取数据的 2 个表是我的表：transfers & trans_payments

转会：

ID        int   
cust_id   int   
tfrom     nvarchar(200) 
tto       nvarchar(200)
price     decimal(18, 2)
tax       decimal(18, 2)
final     Calculated 
tnumber   nvarchar(30)
note      nvarchar(MAX)
date      date

trans_payments：

ID       int
cust_id  int
value    decimal(18, 2)
method   nvarchar(30)
note     nvarchar(MAX)
date     date

假设我有这些数据：

转会：

ID    cust_id   final       date    
1      5        3000     22-09-2020  
2      5        1500     25-09-2020 
3      10       4000     28-09-2020

trans_payments：

ID    cust_id   value       date  
1      5        1000     22-09-2020
2      5        1500     23-09-2020
3      5        1000     01-10-2020
4      10       1000     28-09-2020
5      10       2000     01-10-2020

我想创建一个视图来显示客户对购买和付款的操作，如下所示：

客户 5：

cust_id   final    value    Balance    date      
5        3000        0       3000     22-09-2020 --- > Purchases 
5         0        1000      2000     22-09-2020 --- > payment
5         0        1500      500      23-09-2020 --- > payment
5        1500        0       2000     25-09-2020 --- > P
5         0        1000      1000     23-09-2020 --- > payment purchases  

最后一行是客户的最终余额

我试过了：

CREATE VIEW customer_account_summary as 
WITH Tb0 as
( SELECT ID,date,cust_id,final,0'value' from transfers
        UNION
        SELECT ID,date,cust_id,0'final',value from trans_payments
)

, Tb1 as
( 
    SELECT ID,date,cust_id,final,value,Row_Number() over (order by date asc) as [OrderId]
        FROM    
            Tb0
)

SELECT TOP 1000000 T1.ID,T1.cust_id,T1.date,T1.final,T1.value,(Sum(T2.final) - Sum(T2.value)) as Balance FROM Tb1 as T1
            INNER JOIN
                Tb1 as T2
                ON T1.[OrderId] <= T2.[OrderId]
                Group By T1.ID,T1.cust_id,T1.date,T1.final,T1.value
                Order by [date] 

但我有一个问题，如果 2 位客户在同一日期付款，则付款将为 2 位在同一日期付款的客户计算，我尝试为 2 位客户添加 ID 以防止查询对数据进行分组但我'我仍然面临平衡错误。

我怎样才能以正确的方式做到这一点？

Answer 1

我认为是union all 和一个窗口sum()：

select cust_id, final, value, date,
    sum(balance) over(partition by cust_id order by date, seq) balance
from (
        select cust_id, final, 0, final balance, date, 0 from transfers
        union all
        select cust_id, 0, value, -value, date, 1 from trans_payments
) t (cust_id, final, value, balance, date, seq)
order by cust_id, date, seq

当两个表中都有给定日期的行时，这会将转移放在首位。

Demo on DB Fiddle：

cust_id |决赛 |价值 |日期 |平衡 ------: | ----: | ----: | :--------- | ------: 5 | 3000 | 0 | 2020-09-22 | 3000 5 | 0 | 1000 | 2020-09-22 | 2000 5 | 0 | 1500 | 2020-09-23 | 500 5 | 1500 | 0 | 2020-09-25 | 2000 5 | 0 | 1000 | 2020-10-01 | 1000 10 | 0 | 2000 | 2020-01-01 | -2000 10 | 4000 | 0 | 2020-09-28 | 2000 10 | 0 | 1000 | 2020-09-28 | 1000

您可以使用where 子句过滤给定客户。