【发布时间】:2012-02-21 14:06:29
【问题描述】:
我有以下 NSDictionary 数据:
{
"ADDED_DATE" = "2011-02-04 00:56:44.732014";
"ADDED_LOGON" = ABCD;
"AGENT_BROKER_IND" = N;
"ALLOCATION_IND" = AUTOPROP;
"BILLPRINT_DLVY_IND" = PAPER;
"BILLPRINT_LOCATION_NAME" = "COMPANY ABC";
"BILLPRINT_LVL_CIM" = 05852015;
"BILL_DUE_DT" = "2011-02-01";
"BILL_LOGO_CD" = XXLOGO;
"BILL_PERIOD_MONTH" = 02;
"BILL_PER_BEG_DT" = "2011-02-01";
"BILL_PER_END_DT" = "2011-02-28";
"BILL_RUN_DT" = "2011-02-03";
"BILL_TOTAL_PREMIUM" = "342.84";
IDX = ".000339709222474931";
"LIST_BILL_CASE_NUM" = 0318T4;
"LIST_BILL_CIM" = 05852019;
"OWNING_CARRIER" = WX;
"PAST_DUE_DT" = "2011-03-04";
"REMIT_CYCLE" = MONTHLY;
"RUN_NUMBER" = 1;
"TOTAL_ADJUSTMENTS" = "0.00";
"TOTAL_AMOUNT_DUE" = "685.68";
"TOTAL_CURRENT_CHARGES" = "342.84";
"TOTAL_PASTDUE_AMOUNT" = "342.84";
},
{
"ADDED_DATE" = "2010-12-04 08:20:45.292516";
"AGENT_BROKER_IND" = N;
"ALLOCATION_IND" = AUTOPROP;
"BILLPRINT_DLVY_IND" = WEBPORTAL;
"BILLPRINT_LOCATION_NAME" = "ANCHOR ABC";
"BILLPRINT_LVL_CIM" = 05721991;
"BILL_DUE_DT" = "2010-12-15";
"BILL_FORM_TYPE_CD" = FE4;
"BILL_LOGO_CD" = XXLOGO;
"BILL_PERIOD_MONTH" = 01;
"BILL_PER_BEG_DT" = "2011-01-01";
"BILL_PER_END_DT" = "2011-01-31";
"BILL_RUN_DT" = "2010-12-03";
"BILL_TOTAL_PREMIUM" = "277.96";
IDX = ".000389371998789428";
"LIST_BILL_CASE_NUM" = 9858Q8;
"LIST_BILL_CIM" = 05721991;
"OWNING_CARRIER" = FE;
"PAST_DUE_DT" = "2010-12-31";
"REMIT_CYCLE" = MONTHLY;
"RUN_NUMBER" = 1;
"TOTAL_ADJUSTMENTS" = "0.00";
"TOTAL_AMOUNT_DUE" = "277.96";
"TOTAL_CURRENT_CHARGES" = "277.96";
"TOTAL_PASTDUE_AMOUNT" = "0.00";
},
我正在尝试弄清楚如何将这些数据转换为数组。在这个例子中,我需要将它分解为 2 个数组,这些数组填充了它的数据(希望有意义)。
我可以像这样遍历数据:
NSString *key;
for (key in finalDict) {
NSLog(@"%@", key);
}
我在“key”中获取每个“数组”数据......但是如何将它从那里分解成它自己的数组?对不起,如果我感到困惑。 =)
感谢您的帮助!
【问题讨论】:
-
你想完成什么。另外,如果你想要单独的数组,你想要一个数组数组还是每个数组单独?
-
我正在尝试获取这些数据......并在 UITableView 中使用它。每个数据“数组”都是它自己的行。
-
我认为最好有一个数组数组,但我对此很陌生(但学得很快),所以最好在 UITableView 上使用。非常感谢您的帮助!
-
那么字典中的每个条目都会是一个 TableView 单元格吗?换句话说,每个单元格将包含一个“ADDED_DATE”、“AGENT_BROKER_IND”等?
标签: iphone ios nsarray nsdictionary