SDL - 为什么移动鼠标会改变按钮状态？答案

【问题标题】：SDL - Why moving the mouse changes button state?SDL - 为什么移动鼠标会改变按钮状态？
【发布时间】：2013-08-09 16:40:29
【问题描述】：

我在使用 Simple Directmedia Layer 库时遇到问题。以下代码在按下鼠标按钮时在屏幕上绘制一个块：

SDL_Event event;
while(running){
    while(SDL_PollEvent(&event)){
        while(event.button.state == SDL_PRESSED){

            SDL_PollEvent(&event);

            //where to draw                
            boxRect.x = event.motion.x;
            boxRect.y = event.motion.y;

            //Draw to screen
            SDL_FillRect(display,&boxRect,boxColor);
            SDL_Flip(display);
        }
        // ...
    }
    // ...
}

在我移动鼠标之前它工作正常，为什么移动鼠标会使event.button.state 不真实？

如何同时使用两者（即按下按钮时继续绘图）？

【问题讨论】：

标签： c sdl

【解决方案1】：

您的代码的问题是您调用了两次SDL_PollEvent（记录在here）。如文档中所述：

如果 event 不为 NULL，则从队列中删除下一个事件并存储在 event 指向的 SDL_Event 结构中。

稍微重新排列你的代码，比如去掉第二个SDL_PollEvent，为点击、移动、释放和从输入泵中提取渲染创建适当的流程应该会给你这样的结果：

SDL_Event Event;
while(running)
{
    while(SDL_PollEvent(&Event))
    {
        switch(Event.type)
        {
            // Handle your drawing with a simple state machine:
            case SDL_MOUSEBUTTONDOWN:
            {
                if(Event.button.button == SDL_BUTTON_LEFT)
                {
                    if(stateMachine == Released)
                    {
                        // ... begin drawing
                        stateMachine = Dragging
                    }
                }
                break;
            }
            case SDL_MOUSEMOTION:
            {
                if(stateMachine == Dragging)
                {
                    // ... update the extends of your rect
                }
            }
            case SDL_MOUSEBUTTONUP:
            {
                if(Event.button.button == SDL_BUTTON_LEFT)
                {
                    if(stateMachine != Released)
                    {
                        // ... finalize drawing... add the rect to a list? flush it?
                        stateMachine = Released;
                    }
                }
            }
            case SDL_QUIT:
            {
                running = false;
                break;
            }
        }
    }

    // Outside of your event pumping, update the graphics
    SDL_FillRect(display,&boxRect,boxColor);
    SDL_Flip(display);
}

【讨论】：

【解决方案2】：

event.button.state 是位掩码。它被声明为char，可以保存代表按钮不同状态的八位。

typedef struct{
  Uint8 type;
  Uint8 state;
  Uint16 x, y;
  Sint16 xrel, yrel;
} SDL_MouseMotionEvent;

【讨论】：

感谢您的回复。我不明白为什么它会影响结构的其他部分。您能否提供一个在按下鼠标时绘制块的代码示例？我更新了代码。

【解决方案3】：

感谢 emartel 的回答，它按预期工作，代码如下：

SDL_Event event;
int drawing = 0;

while(running){
    while(SDL_PollEvent(&event)){
        switch(event.type){

            //starts drawing when any mouse button is pressed
            case SDL_MOUSEBUTTONDOWN:
                drawing = 1;
                boxRect.x = event.button.x;
                boxRect.y = event.button.y;
            break;


            //keeps drawing while no button is released
            case SDL_MOUSEMOTION:
                if(drawing == 1){
                    boxRect.x = event.motion.x;
                    boxRect.y = event.motion.y;
                }
            break;


            //stops drawing when any button is released
            case SDL_MOUSEBUTTONUP:
                drawing = 0;
            break;


            case SDL_QUIT:
                running = 0;
            break;

        }

    }

    //draws to screen
    if(drawing == 1){
        SDL_FillRect(display,&boxRect,boxColor);
        SDL_Flip(display);
    }
}

【讨论】：