使用 sql 获取具有匹配技能的人员列表

Question

I have 2 tables Task and Skill

任务表：

Task_id	skill
1	x
1	y
2	x
2	z

技能：

agent_name	skills
abc	x
abc	y
def	y
def	k
pqr	x
pqr	y
abc	z

我想要可以处理某项任务的所有代理的列表， 这里代理 abc 和 pqr 具备完成任务 1 的所有技能

Answer 1

如果您想选择具有超过所需技能的agent_name（但包含所需技能），您应该更改开启条件：

on t2.skills_for_task LIKE CONCAT('%', t1.skill_for_task, '%') ;

SELECT agent_name,task_id,skill_for_task
FROM
          (
             select task_id,group_concat(skill) as skill_for_task
             from task
             group by task_id
           ) as t1 
           
           INNER JOIN 
           
           (
             select agent_name,group_concat(skills) as skills_for_task
             from skill
             group by agent_name
           
           ) as t2 
on t2.skills_for_task LIKE CONCAT('%', t1.skill_for_task, '%') ;  

演示：https://dbfiddle.uk/?rdbms=mysql_8.0&fiddle=66efe141b29b6d38ddf95e13b8ff1e68

结果：

agent_name    task_id skill_for_task
abc            1            x,y
pqr            1            x,y  

开启Postgres 13

SELECT agent_name,task_id,skill_for_task
FROM
          (
             select task_id,string_agg(skill,',') as skill_for_task
             from task
             group by task_id
           ) as t1 
           
           INNER JOIN 
           
           (
             select agent_name,string_agg(skills,',') as skills_for_task
             from skill
             group by agent_name
           
           ) as t2 
on t2.skills_for_task LIKE CONCAT('%', t1.skill_for_task, '%') ;

演示：https://dbfiddle.uk/?rdbms=postgres_13&fiddle=b1df46bb1bf750d7ec0ade979ba9a465

结果：

agent_name    task_id skill_for_task
abc            1            x,y
pqr            1            x,y