【发布时间】:2015-01-09 18:08:20
【问题描述】:
我正在打开一个弹出窗口,我想从现有的弹出窗口中打开另一个弹出窗口。但是当我点击图片按钮时,什么也没有发生。
protected void ViewImageButton_Click(object sender, ImageClickEventArgs e)
{
ImageButton ViewTicketImageBtn = sender as ImageButton;
GridViewRow GridViewRow = (GridViewRow)ViewTicketImageBtn.NamingContainer;
try
{
//some code here
this.ClientScript.RegisterClientScriptBlock(this.GetType(), "clientScript", "<script type=\"text/javascript\">viewTicketDetails();</script>");
}
}
这是我在 Site.Master 中的代码。对于 viewTicketDetails()
var win;
function viewTicketDetails() {
win = window.open('ViewTicketDetailsPage.aspx'
, 'TicketDetails'
, 'width=1040, height=600, innerHeight=600, location=no, menubar=no, status=no, titlebar=no, scrollbars=yes, left=0'
, '_blank');
win.focus();
};
【问题讨论】: