解析错误：语法错误，意外的 T_STRING，期待 ',' 或 ';'在 C:\wamp\www\Giusti\AssignmentExample.php 第 24 行答案

【问题标题】：Parse error: syntax error, unexpected T_STRING, expecting ',' or ';' in C:\wamp\www\Giusti\AssignmentExample.php on line 24解析错误：语法错误，意外的 T_STRING，期待 ',' 或 ';'在 C:\wamp\www\Giusti\AssignmentExample.php 第 24 行
【发布时间】：2011-02-04 13:34:14
【问题描述】：

我正在自学 PHP，并根据我的书完成这些项目。但是我完全按照所示输入了代码，但仍然得到相同的错误。我也多次重新检查代码。对不起，我是个菜鸟，但我真的被困住了。如果有人能解释什么是错的并解决这个问题，将不胜感激，谢谢=)

代码：

<!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0
STRICT//EN"
"http://www.w3.org/TR/xhtml1/DTD/xhtml1-strict.dtd">
<html xmlns="http://www.w3.org/1999/xhtml">
<head>
<title>php</title>
<meta http-equiv="content-type"
    content="text/html; charset=iso-8859-1" />
</head>
<body>

<?php
$ChangingVar = 100;
$ChangingVar += 50;
echo "<p>";
echo "Variable after addition assignment =
$ChangingVar<br />";
$ChangingVar -= 30;
echo "Variable after subtraction assignment =
$ChangingVar<br />";
$ChangingVar /= 3;
echo "Variable after division assignment = 
$ChangingVar *= 8;
echo "Variable after multiplication assignment =
$ChangingVar<br />";
$ChangingVar %= 300;
echo "Variable after modulus assignment =
$ChangingVar</p>";


?>

</body>
</html>

【问题讨论】：

标签： php syntax

【解决方案1】：

您缺少$ChangingVar<br />";：

$ChangingVar /= 3;
echo "Variable after division assignment = 
$ChangingVar<br />";     // <-- here
$ChangingVar *= 8;

请注意，页面上不会显示换行符，所以要写

echo "Variable after division assignment = $ChangingVar<br />";

可能更容易阅读和验证；）

【讨论】：

【解决方案2】：

你在“$ChangingVar *= 8;”之后写错了。我试图修复它。看看吧。

<?php
$ChangingVar = 100;

$ChangingVar += 50;

echo "<p>";

echo "Variable after addition assignment =

$ChangingVar<br />";

$ChangingVar -= 30;

echo "Variable after subtraction assignment =

$ChangingVar<br />";

$ChangingVar /= 3;

echo "Variable after division assignment =

$ChangingVar<br />";

$ChangingVar *= 8;

echo "Variable after multiplication assignment =

$ChangingVar<br />";

$ChangingVar %= 300;

echo "Variable after modulus assignment =

$ChangingVar</p>";

?>

【讨论】：