如何比较多个对象的值？

Question

我想比较我保存在数组中的对象的值。

我知道我可以使用来自每个对象的值创建新数组，但我正在尝试找到一些方法来做到这一点而不创建它们。

考虑我们有这样的情况：

soldiers[first, second, third]
first{name: John, shooting: 95, combat: 50, tactic: 88}
second{name: Arnold, shooting: 97, combat: 72, tactic: 68}
third{name: William, shooting: 87, combat: 86, tactic: 97}

我想从上面提供的士兵中选出最好的士兵 - 但我无法创建一个评分（即平均）。

会有一些士兵必须满足的条件——例如：战斗中至少有 60 点（不管其他属性是否为 100）。

所以我试图找到方法来比较多个属性并只返回一名士兵的姓名。

我会感激每一个提示。谢谢！

Answer 1

我用 cmets 给你做了一个例子。如果这将您推向正确的方向，或者您是否需要任何其他帮助，请告诉我。

const soldiers = [{
    name: "John",
    shooting: 95,
    combat: 50,
    tactic: 88
  },
  {
    name: "Arnold",
    shooting: 97,
    combat: 72,
    tactic: 68
  },
  {
    name: "William",
    shooting: 87,
    combat: 86,
    tactic: 97
  }
];

const filteredSoldiers = soldiers
  .filter(soldier => soldier.combat > 60) // Find every soldier where combat is higher than 60
  .map(soldier => {
    return {
      name: soldier.name,
      average: (soldier.combat + soldier.tactic + soldier.shooting) / 3
    };
    // map will return an array with the filtered soldiers, and we put their average and their name in there
  })
  .sort((a, b) => b.average - a.average);
// Lastly we sort them high to low by their average score

console.log(
  filteredSoldiers.length > 0 ? filteredSoldiers[0].name : 'No soldiers with combat score higher thn 60'
);

jsfiddle

在过滤条件中你当然可以添加更多的检查。

Answer 2

您需要通过所有项目并选择最有价值的；

注意有些士兵可以有相似的值，这就是为什么values.name 是数组

let a = {
    name: "John", shooting: 95, combat: 50, tactic: 88
};
let b = {
    name: "Arnold", shooting: 97, combat: 72, tactic: 68
};
let c = {
    name: "William", shooting: 87, combat: 86, tactic: 97
};
let soldiers = [a, b, c];
let values = {
    shooting: {
        name: [],
        score: 0
    },
    combat: {
        name: [],
        score: 0
    },
    tactic: {
        name: [],
        score: 0
    }
};

soldiers.map((item) => {
    ['shooting', 'combat', 'tactic'].forEach(name => {
        if (item[name] > values[name].score) {
            values[name].name = [item.name];
            values[name].score = item[name];
        } else if (item[name] === values[name].score) {
            values[name].name.push(item.name);
        }
    });
});

console.log(values);