【发布时间】:2015-09-24 16:29:32
【问题描述】:
以下是用于获取 ns1: 问题的测试代码,我总是得到一个没有任何内容的对象。
如果我删除这两个 [XmlType] 和 [XmlRoot] 就会出错。
我相信有些人可能已经面临找不到正确搜索词的问题了,
希望它是一件简单的事情。
[XmlType(AnonymousType = true, Namespace = "http://itaintworking.com/test/")]
[XmlRoot(Namespace = "http://itaintworking.com/test/", IsNullable = false)]
public class Clients
{
public string clientName { get; set; }
public addressDetails addressDetails { get; set; }
}
public class addressDetails
{
public int addressId { get; set; }
}
[Test(Description = "Serialization Exception")]
public void CheckDeserializer()
{
var strXml =
"<?xml version=\"1.0\" encoding=\"UTF-8\" standalone=\"yes\"?><ns1:Clients xmlns:ns1=\"http://itaintworking.com/test/\" xmlns:xsi=\"http://www.w3.org/2001/XMLSchema-instance\" ><clientName>hello</clientName><addressDetails><addressId>98989</addressId></addressDetails></ns1:Clients>";
var x = XmlSerializer<Clients>.Deserialize(strXml);
Assert.IsNotNull(x);
}
我正在使用一些使用泛型的代码,还有另一种方法默认为 UTF8 编码,xmlReaderSetting 为 null。
/// <summary>
/// Deserializes a XML string into an object
/// </summary>
/// <param name="xml">The XML string to deserialize</param>
/// <param name="encoding">The encoding</param>
/// <param name="settings">XML serialization settings. <see cref="System.Xml.XmlReaderSettings"/></param>
/// <returns>An object of type <c>T</c></returns>
public static T Deserialize(string xml, Encoding encoding, XmlReaderSettings settings)
{
if (string.IsNullOrEmpty(xml))
throw new ArgumentException("XML cannot be null or empty", "xml");
var xmlSerializer = new XmlSerializer(typeof(T));
using (var memoryStream = new MemoryStream(encoding.GetBytes(xml)))
{
using (var xmlReader = XmlReader.Create(memoryStream, settings))
{
return (T)xmlSerializer.Deserialize(xmlReader);
}
}
}
【问题讨论】: