NHibernate - sql 表别名不一致

Question

有没有办法预测nhibernate在生成sql时会为表生成什么别名？

理论上它应该是 'this_'、'this_1_' 等，它会很棒，但我发现当我在映射中使用 Join 时它有点随机。

例如在集成测试中我得到这样的结果：

table1 this_ 
left outer join
   table2 o this_1_
        on this_.id=this_1_.t1id
left outer join
    table3  this_2_ 
        on this_.id=this_2_.t1id
left outer join
    table4 this_3_ 
        on this_.id = this_3_.t1id
left outer join
    table5 somealiasbasedonrootentity_2_
        on this_.id=somealiasbasedonrootentity_2_.t1id

但是当我在网络服务器上运行相同的映射时...所有别名都是 somealias_, somealias_1_ 等等

难道不应该至少……更加一致吗？

在映射中使用任何类型的“位置”或“公式”变得非常困难（甚至不可能）

---编辑：我想通过映射实现的示例查询

select 
  t1.a, t2.a, (select max(t3.value) where t3.id=t2.t3id) 
from table1 t1 
  left join table2.t2 on t2.t1id=t1.id;

--- 编辑这里的（几乎是最新的）映射： 我知道它很大，但我打算将其用于报告目的。 （顺便说一句，它不是最新版本）

public class ClaimHistoryMap : ClassMap<ClaimHistory>
    {
        public ClaimHistoryMap()
        {
            Table("wts_claim");
            ReadOnly();
            Not.LazyLoad();
            Id(x => x.Id, "claimid");
            Map(x => x.ClaimNo, "claimNo");
            Map(x => x.DateCompleted, "ModificationDate");
            Map(x => x.DateOfDispatch, "DateOfDispatch");
            Map(x => x.DateProcessed, "ModificationDate");
            Map(x => x.Status, "status");
            Map(x => x.WorkOrderNo, "ServiceWorkOrder");
            Map(x => x.SerialNo, "serialNo");
            Map(x => x.IsEnabled, "bStatus");
            Map(x => x.InvoiceNo, "InvoiceNo");
            Map(x => x.ServiceCoverage).Formula(
                @"(Select c.coveragename from wts_servicecoverage as c where c.servicecoverageid=servicecoverageid)");
            Join("wts_site_info",x=>
                             {

                                     x.Optional().KeyColumn("claimid");
                                     x.Map(s => s.CustomerName, "CustomerName");
                                     x.Map(s => s.CustomerAddress, "Address");
                                     x.Map(s => s.CustomerCity, "City");
                                     x.Map(s => s.CustomerPhone, "Phone");
                                     x.Map(s => s.CustomerZip, "Zip");
                                     x.Map(s => s.ReportComplaint, "Complaint");
                                     x.Map(s => s.TechnicianName, "TechName");

                                     x.Map(s => s.Model)
                                         .Formula(@"(Select mo.Model from WTS_Product mo where mo.ProductId=this_1_.ProductId)");
                                     x.Map(s => s.CustomerState)
                                         .Formula(@"(Select st.statename from wts_state st where st.stateid=this_1_.state)");
                                 });
        Join("wts_grand_total", x =>
                                    {
                                        x.Optional().KeyColumn("claimid");
                                        x.Map(s => s.TotalCharge, "total");
                                        x.Map(s => s.FreightCharge, "Frieght");
                                        x.Map(s => s.PartsCharge, "Parts");
                                        x.Map(s => s.HandlingFee, "Handling");
                                        x.Map(s => s.SalesTax, "Mix");
                                    });
        Join("wts_labour_travel", x =>
        {
            x.Optional().KeyColumn("claimid");
            x.Map(s => s.TravelCharge).Formula("traveltotal+travelovertotal+MilageRegular+MilageOvertime+supmileagehour+supmileageoverhour");
            x.Map(s => s.TravelTime).Formula("TravelHourRegular+TravelHourOvertime+suptravelhour+suptraveloverhour");
            x.Map(s => s.LaborCharge).Formula("labortotal+laborovertotal");
            x.Map(s => s.LaborTime).Formula("LaborHoursRegular+LaborHoursOvertime+suplaborhour+suplaboroverhour");
            x.Map(s => s.TripsNo, "trips");
            x.Map(s => s.TruckCharge).Formula(
                "(select max(ltr.TruckRate) from wts_labour_travel_rate ltr where ltr.LabourTravelId = this_3_.LabourTravelId)");
        });

        Map(x => x.WasModified).Formula(
            "(select count(comm.claim_id) from wts_claim_status comm where comm.claim_id=this_.claimid and comm.Status=3)");
        References(x => x.User, "entryBy").Fetch.Join().Not.LazyLoad();

        HasMany(x => x.PartNo).KeyColumn("claimid").Table("wts_general_part").Element("partNo");
        HasMany(x => x.Repairs).KeyColumn("claimid").Table("wts_Claim_Resolution").Element("resolutionDesc");
    }
}

Answer 1

您不需要在映射中引用别名，只需引用您感兴趣的属性。例如，如果您有一个 FluentNHibernate 映射，该映射具有一个名为“SomeValue”的属性，您可以创建一个 where映射中的限制如下：

Where("SomeValue = 1");

类似的事情也适用于 XML 文件映射。