在我的 java tictactoe 游戏中无法获得正确的输出

Question

大家好，我的作业真的需要帮助。我试过这样做，但我无法弄清楚。

起跑板：

1  2  3     

4  5  6     

7  8  9

结果愿望：

x  2  3

o  x  6

7  o  x

但是每次我执行时，只要有赢家，我总是会得到以下信息：

x 2 3

o x 6 

7 o 9

最后，如何计算获胜最多的玩家的胜率？

限制：

• 井字游戏必须使用二维数组。 （我知道我没有使用二维数组，因为我不知道如何让编译器接受来自二维数组的 1-9 输入。）

• 这个问题你不能使用类。

• 如果你愿意，你可以使用静态方法。

  import java.util.Scanner;
  public class TicTacToe {    public static String answer = "yes";
  public static Scanner input = new Scanner(System.in);
  public static String getName(int noPlayer) {
      System.out.print("Enter name of Player " + noPlayer + ": ");
      return input.next();
  }
  
  public static int getMove(String board[], String player) {
      printBoard(board);
      System.out.print("Enter move for " + player + ": ");
      int move = input.nextInt() - 1;
      while (moveTaken(board, move)) {
          System.out.println("Move taken.");
          System.out.print("Enter move for " + player + ": ");
          move = input.nextInt() - 1;
      }
      return move;
  }
  public static String gameResult(String board[]) {
      final int checkWin[][] = {{0, 1, 2}, {3, 4, 5}, {6, 7, 8},
                                      {0, 3, 6}, {1, 4, 7}, {2, 5, 8},
                                      {0, 4, 8}, {2, 4, 6}};
      for (int[] i: checkWin) {
          if (board[i[0]].equals(board[i[1]]) && board[i[0]].equals(board[i[2]]) && board[i[1]].equals(board[i[2]])) {
              if (board[i[0]].equals("O")) {
                  return "X wins";
              }
              else {
                  return "O wins";
              }
          }
      }
      if (!board[0].equals("1") && !board[1].equals("2") && !board[2].equals("3") &&
          !board[3].equals("4") && !board[4].equals("5") && !board[5].equals("6") &&
          !board[6].equals("7") && !board[7].equals("8") && !board[8].equals("9")) {
          return "draw";
      }
      return "not completed";
  }
  public static boolean moveTaken(String board[], int move) {
      if (board[move].equals("O") || board[move].equals("X")) {
          return true;
      }
      return false;
  }
  public static void printBoard(String board[]) {
      System.out.println(" " + board[0] + " " + board[1] + " " + board[2] +
                         "\n" +
                         " " + board[3] + " " + board[4] + " " + board[5] +
                         "\n" +
                         " " + board[6] + " " + board[7] + " " + board[8]);
  }
  public static void conclusion(String result, String pO, String pX) {
      if (result.equals("O wins")) {
          System.out.println(pO + " wins!");
  
      }
      else if (result.equals("X wins")) {
          System.out.println(pX + " wins!");
      }
      else {
          System.out.println("Draw.");
      }
  }
  public static void main(String args[]) {
  
        String X = getName(1);
        String O = getName(2);
  
    int count = 1;
    do{   
  
      String nextPlayer = X;
      String board[] = {"1", "2", "3", "4", "5", "6", "7", "8", "9"};
      int move;
          while (gameResult(board).equals("not completed")) {
              move = getMove(board, nextPlayer);
              if (nextPlayer == X) {
                  board[move] = "X";
                  nextPlayer = O;
              }
              else {
                  board[move] = "O";
                  nextPlayer = X;
              }
          }
      System.out.println("game up to date: " + count);
  
     conclusion(gameResult(board), X, O);
  
      System.out.println("Do you want to play again? yes or no");
       answer = input.next();
       count++; 
  
  
  }
      while(answer.equalsIgnoreCase("yes"));
  
  
  
  
    }
  }
  

Answer 1

在执行移动之前，您只能在getMove 中打印板。因此永远不会显示最后一步。

你应该在游戏结束时添加对printBoard的调用。

这是一个可能的添加位置：

...
System.out.println("game up to date: " + count);
printBoard(board);
conclusion(gameResult(board), X, O);
...