【发布时间】:2019-04-02 01:09:26
【问题描述】:
我是python的新手。我正在尝试编写一个程序来参考哈佛和 APA 风格的书籍、书籍章节和期刊文章。我需要能够打印来自用户的条目。
代码显示三个窗口。首先,要求用户选择参考风格(哈佛/APA),当点击按钮时,它会打开第二个窗口,允许用户选择来源(书籍/书籍章节/期刊)。然后打开第三个窗口,允许用户输入所需的信息(作者/年份/标题等)。
在此之后,用户必须单击另一个按钮完成才能看到完整的参考。要可视化执行,请选择哈佛,然后选择 Book,因为我只编写了那部分代码。
from tkinter import *
def book_harvard():
reference = author_entry.get()
reference_1 = year_entry.get()
reference_2 = title_entry.get()
string_to_display = reference + reference_1 + reference_2
print(string_to_display)
def TypeofTextHarvard():
second = Toplevel(first)
first.withdraw()
second.title("Type of Source")
Source = Label (second, text = "What type of source would you like to reference?").grid(column = 1, row = 0)
Book = Button (second, text = "Book", command = Harvard).grid(column = 1, row = 1)
Chapter = Button (second, text = "Book Chapter").grid (column = 1, row = 2)
Journal = Button (second, text = "Journal Article").grid (column = 1, row = 3)
first = Tk()
first.title("Referencing Style")
Reference = Label (first, text = "Which referencing style would you like to use?").grid(column = 1, row = 0)
Harvard = Button (first, text = "Harvard Style", command = TypeofTextHarvard).grid (column = 1, row = 1)
APA = Button (first, text = "APA Style").grid (column = 1, row = 2)
def Harvard():
third = Toplevel()
third.title("book")
author = StringVar()
year = StringVar()
title = StringVar()
author_label = Label(third, text = "Author")
author_entry = Entry(third)
year_label = Label(third, text = "Year")
year_entry = Entry(third)
title_label = Label(third, text = "Title")
title_entry = Entry(third)
button_1 = Button(third, text = "Done", command = book_harvard)
author_label_2 = Label(third, textvariable = author)
year_label_2 = Label(third, textvariable = year)
title_label_2 = Label(third, textvariable = title)
author_label.grid (row = 0, column = 0)
author_entry.grid (row = 0, column = 1)
year_label.grid (row = 1, column = 0)
year_entry.grid (row = 1, column = 1)
title_label.grid (row = 2, column = 0)
title_entry.grid (row = 2, column = 1)
button_1.grid (row = 3, column = 0)
author_label_2.grid (row = 4, column = 1)
year_label_2.grid (row = 4, column = 2)
title_label_2.grid (row = 4, column = 3)
first.mainloop()
但是我得到以下错误:
reference = author_entry.get()
NameError: name 'author_entry' is not defined
【问题讨论】:
-
函数中定义的名称在该函数完成执行后不存在,并且从该函数外部不可见。更长时间地保留事物名称的一种常见方法是创建一个类并分配给实例化类的属性。 (
self.author_entry = Entry(third)然后在另一种方法中您可以执行reference = self.author_entry.get())另一种方法是让您的函数返回任何相关对象并将这些返回的对象分配给您所使用的名称。然后将这些对象传递给其他函数。还有一种方法是使用全局变量。但不要。
标签: python python-3.x tkinter