子类如何调用与子类方法名相同的超类方法？

Question

#include <iostream>
using namespace std;

class Person {
public:
    void sing();
};

class Child : public Person {
public:
    void sing();
};

Person::sing() {
    cout << "Raindrops keep falling on my head..." << endl;
}

Child::sing() {
    cout << "London bridge is falling down..." << endl;
}

int main() {
    Child suzie;
    suzie.sing(); // I want to know how I can call the Person's method of sing here!

    return 0;
}

Answer 1

suzie.Person::sing();

Answer 2

孩子可以使用 Person::sign()。

请参阅 http://bobobobo.wordpress.com/2009/05/20/equivalent-of-keyword-base-in-c/ 以获得很好的解释。