【发布时间】：2016-12-13 15:27:19
【问题描述】：
我有 4 个向量：
list1 <- c("a","b","c","d","e")
list2 <- c("f","g","h","i","j")
list3 <- c("k","l","m","n","o")
list4 <- c("p","q","r","s","t")
我想生成每个组合来选择这 4 个向量中的 2 个，所以我使用了：
combs <- combn(c("a","b","c","d"),2)
然后我想以这些组合（梳子的列）作为参数运行一个函数：
所以第 1 列应该给出 list1 和 list2 的组合，但我希望它作为向量 "a","b","c","d","e","f","g", "h","i","j" 而不是 "list1" "list2"
【问题讨论】：
-
您的问题不清楚。请显示预期结果。也许
combn(c(list1, list2), 2)？ PS：请不要调用向量列表（即使是变量名）。一旦你有了实际的列表对象，这就会让人感到困惑。 -
预期分享输出
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试试
combn(paste0("list", 1:4), 2, FUN = function(x) list(mget(x, envir = .GlobalEnv))) -
预期输出是一个包含 "a","b","c","d","e","f","g","h","i" 的向量,"j"
标签： r