您的问题不够清楚,我猜您的问题是关于如何通过对每个属性进行分组来从用户列表中创建层次结构。
为此,您可以使用 linq 的分组功能。这是第一级的示例,您可以自己重复它以创建层次结构:
var users = new[] {
new {
CompanyName = "c1",
Branch = "b1",
Destination = "d1",
UserName= "u1",
}, new {
CompanyName = "c1",
Branch = "b1",
Destination = "d1",
UserName= "u1",
}, new {
CompanyName = "c1",
Branch = "b1",
Destination = "d1",
UserName= "u1",
}, new {
CompanyName = "c2",
Branch = "b1",
Destination = "d2",
UserName= "u2",
},
};
var data = from u in users
group u by u.CompanyName into ug
select new { Node = ug.Key, Childs = ug };
foreach (var i in data)
{
Console.WriteLine(i.Node);
foreach (var node in i.Childs)
{
Console.WriteLine("\t" + node.UserName);
}
}
这是带有嵌套分组的代码:
var users = new[] {
new {
CompanyName = "c1",
Branch = "b3",
Destination = "d1",
UserName= "u1",
}, new {
CompanyName = "c1",
Branch = "b1",
Destination = "d1",
UserName= "u1",
}, new {
CompanyName = "c1",
Branch = "b1",
Destination = "d1",
UserName= "u1",
}, new {
CompanyName = "c2",
Branch = "b1",
Destination = "d2",
UserName= "u2",
},
};
var data = from u1 in users
group u1 by u1.CompanyName into gByCompanyName
select new
{
Node = gByCompanyName.Key,
Childs = from u2 in gByCompanyName
group u2 by u2.Branch into gByBranch
select new
{
Node = gByBranch.Key,
Childs = from u3 in gByBranch
group u3 by u3.Destination into gByDestination
select new
{
Node = gByDestination.Key,
Childs = from u4 in gByDestination
select new { Node = u4.UserName }
}
}
};
foreach (var n1 in data)
{
Console.WriteLine(n1.Node);
foreach (var n2 in n1.Childs)
{
Console.WriteLine("\t" + n2.Node);
foreach (var n3 in n2.Childs)
{
Console.WriteLine("\t\t" + n3.Node);
foreach (var n4 in n3.Childs)
{
Console.WriteLine("\t\t\t" + n4.Node);
}
}
}
}
Console.ReadLine();
我希望这会有所帮助。