插入值在 mysqli 中不起作用

Question

我创建了两个表，员工和部门。现在，在部门表中，我分配了一个外键，并为雇员表分配了一个 PK。如果查看数据，可以加入表格。

如何在 PHP 中编写查询以进行插入和更新？

我的查询：

?php
include "connect.php";
if(isset($_POST["submit"]))
{
    $fname  = $_POST["fname"];
    $dept   = $_POST["dept"];


    $result = mysqli_query($mysqli, "INSERT INTO employee ( fname, department)
            (SELECT fname, department FROM employee LEFT JOIN department ON employee.id=department.dept_id) values ( '$fname', '$dept')");

    if($result)
        {
            echo "<script>alert('New employee register successfully!')</script>";
            echo "<script>window.open('register.php','_self')</script>";
        }
    else 
        {
            echo "<script>alert('something went wrong!')</script>";
        }
    }
?>

Answer 1

$result = mysqli_query($mysqli, "INSERT INTO employee (`fname`, `dept`)
VALUES ('$fname','$dept')");
if($result)
    {
        echo "<script>alert('New employee register successfully!')</script>";
        echo "<script>window.open('register.php','_self')</script>";
    }

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