【发布时间】:2014-07-29 14:00:52
【问题描述】:
如果我写这个:
<ul data-role="listview" data-inset="true">
<li>
<a href="#">
<img src="PIC/999.jpeg">
<h2>Google Chrome</h2>
<p>Google Chrome is a free, open-source web browser. Released in 2008.</p>
</a>
<a href="#">Some Text</a>
</li>
<li>
<a href="#">
<img src="PIC/999.jpeg">
<h2>Mozilla Firefox</h2>
<p>Firefox is a web browser from Mozilla. Released in 2004.</p>
</a>
<a href="#">Some Text</a>
</li>
</ul>
我看到了漂亮的设计
但我的移动网络需要这个:
<script>
function XX() {
if (window.XMLHttpRequest) {// code for IE7+, Firefox, Chrome, Opera, Safari
xmlhttp = new XMLHttpRequest();
}
else {// code for IE6, IE5
xmlhttp = new ActiveXObject("Microsoft.XMLHTTP");
}
xmlhttp.open("GET", "1.xml", false);
xmlhttp.send();
xmlDoc = xmlhttp.responseXML;
$("#ZIBI").empty();
var ALL;
var ID,Fname, Lname, Phone,Car;
var x = xmlDoc.getElementsByTagName("men");
for (i = 0; i < x.length; i++) {
try{ID = x[i].getElementsByTagName("ID")[0].childNodes[0].nodeValue;}
catch (err) { ID = "0";}
try{Fname = x[i].getElementsByTagName("Fname")[0].childNodes[0].nodeValue;}
catch (err) { Fname = "0"; }
try{Lname = x[i].getElementsByTagName("Lname")[0].childNodes[0].nodeValue;}
catch (err) { Lname = "0"; }
try{Phone = x[i].getElementsByTagName("S_phone")[0].childNodes[0].nodeValue;}
catch (err) { Phone = "0"; }
try { Car = x[i].getElementsByTagName("car")[0].childNodes[0].nodeValue; }
catch (err) { Car = "0"; }
ALL =
'<li>' +
'<a href="#">' +
'<img src="PIC/' + ID + '.jpeg">' +
'<p class="nam">' + Fname + " " + Lname + '</p>' +
//'<p class="des">' + Lname + '</p>' +
'<p class="phn">' + Phone + '</p>' +
'<p class="crr">' + Car + '</p>' +
'<hr>' +
'</a>' +
'</li>'
$("#ZIBI").append(ALL);
}
}
</script>
<ul data-role="listview" data-inset="true" id="ZIBI" data-autodividers="true" data-filter="true" ></ul>
我看到了这个丑陋的设计
【问题讨论】:
标签: javascript jquery jquery-mobile