C# 在方法调用中扩展泛型类

Question

我正在尝试编写一个传递泛型参数的方法，该方法将使用泛型参数扩展一个类，但我不想将第二个泛型参数传递给该方法。有没有办法在不传递两个通用参数的情况下实现我想要做的事情？

// this base doesn't work because it expects a BaseReportViewModel<D> 
// I don't want to have to pass in two generic arguments from the child controller
// this is what I don't want to do: this.ReportView<Report1ViewModel, Report1Data>(viewModel);
// I want to ONLY have to pass in a single generic argument. 

public class BaseController {
  // the below line won't compile because it expects a generic type to be passed to BaseReportViewModel<>
  public ActionResult ReportView<T>(T viewModel) where T : BaseReportViewModel {
    viewModel.ReportGroup = this.ReportGroup;
    viewModel.ReportTitle = this.ReportTitle;
    return this.View(viewModel);
  }
}

public class ChildController {  
  var viewModel = new Report1ViewModel();               
  viewModel.Data = new Report1Data();
  return this.ReportView<Report1ViewModel>(viewModel);            
}

public class BaseReportViewModel<T> : BaseViewModel where T : ReportBaseData {
  public string ReportGroup { get; set; }
  public string ReportTitle { get; set; }
  public T Data { get; set; }
}

public class Report1ViewModel : BaseReportViewModel<Report1Data> {
}

public class Report1Data : BaseReportData {
}

Answer 1

我想你想要这样的东西

public ActionResult ReportView<T>(BaseReportViewModel<T> viewModel) 
    where T : ReportBaseData 

旁注：您也不需要在 this.ReportView<Report1ViewModel>(viewModel); 调用中传递类型，只需 ReportView(viewModel); 就足够了，因为类型应该从参数派生。