双重计数选择返回错误的结果

Question

您好，我正在使用以下查询来显示 id 与第一个表中的数字相同的行数，我还有 2 个表。如果我只留下一个计数，一切都可以正常工作，但使用双重计数选择我会得到相同的结果，这是错误的：

'SELECT c.*, count(s.userID) as count_consulta, count(a.userID) as count_asesoria
   FROM users as c 
   LEFT JOIN consulta AS s ON s.userID = c.userID 
   LEFT JOIN asesoria AS a ON a.userID = c.userID
   GROUP BY c.userID DESC'

我得到了这个：

count_consulta = 15
count_asesoria = 15

应该在哪里

count_consulta = 3
count_asesoria = 5

欢迎任何帮助。谢谢！

Answer 1

有了“欢迎任何帮助”的声明，我把它扔出去看看它是否符合你的意思。

$sql="select *,
    ( select count( distinct s.`userID` ) from `consulta` ) as 'count_consulta',
    ( select count( distinct a.`userID` ) from `asesoria` ) as 'count_asesoria'
    from `users` c
        left outer join `consulta` s on s.`userID`=c.`userID`
        left outer join `asesoria` a on a.`userID`=c.`userID`
    group by c.`userID` desc;";