无法快速获取视图控制器的索引，它是 UInavigationController 的视图控制器

Question

我想检查导航控制器的 viewcontroller 是否包含 ABC Viewcontroller 是否包含想要弹出到 ABC 的前一个 viewcontroller 否则想要 popviewcontroller

class Common:UIViewController{
    class func returnclassviewcontroller(storybordname:String,classname:String)->UIViewController{
        let sb = UIStoryboard.init(name: storybordname, bundle: nil)
        var viewcontroller:UIViewController!
        viewcontroller = sb.instantiateViewController(withIdentifier: classname)
        return viewcontroller

      }
    }
    if let abcclass = Common.returnclassviewcontroller(storybordname: Constant.StoryboardNameLead, 
              classname: "ABC") as? ABC{

            if(self.navigationController?.viewControllers.contains(abcclass)?? false){
            if let index = self.navigationController?.viewControllers.indexOf(abcclass){

    self.navigationController?.popToViewController(self.navigationController?.viewControllers[index-1] ?? 
    self, animated: true)
    }else{
                              self.navigationController?.popViewController(animated: true)                                           
     }
                            }
                        }else{
                    self.navigationController?.popViewController(animated: true)
                        }
``
I am reaching to else part everytime , Though ABC Class is in naviagtion constorller's subview controller never reach to "self.navigationController?.popToViewController(self.navigationController?.viewControllers[index-1] ?? 
    self, animated: true)"

Answer 1

index(of element: Element) -> Int? 已弃用.. 所以使用firstIndex(of element: Element) -> Int?

firstIndex(of:)

返回指定值出现在 收藏。

 if let index =navigationController?.viewControllers.firstIndex(of: abcclass) {
     // do what you want to with index
    }