Mulesoft：如何在 mule 4 dataweave 2.0 中使用相同的键映射和分组数据答案

【问题标题】：Mulesoft: How to map and group data with same key in mule 4 dataweave 2.0Mulesoft：如何在 mule 4 dataweave 2.0 中使用相同的键映射和分组数据
【发布时间】：2020-05-10 06:22:04
【问题描述】：

我可以用 for each 和 sum 过滤器值转换我的输入以获得输出格式（许多数据将添加到数组中）。但是每个人都花了很多时间。如何更快地将其与转换消息映射？请帮我解决一下。

我的意见：

{
  "PART_NUMBER": "501-239",
  "HUBS": [
    {
      "NAME": "SUK",
      "SUB_INVENTORIES": [
        {
          "NAME": "FG",
          "LOCATORS": [
            {
              "NAME": "FGACCESSORY"
            }
          ]
        }
      ]
    },
    {
      "NAME": "SUK",
      "SUB_INVENTORIES": [
        {
          "NAME": "FG",
          "LOCATORS": [
            {
              "NAME": "FGPB"
            }
          ]
        }
      ]
    },
    {
      "NAME": "SUK",
      "SUB_INVENTORIES": [
        {
          "NAME": "RAWWIP",
          "LOCATORS": [
            {
              "NAME": "FLOOR"
            }
          ]
        }
      ]
    },
    {
      "NAME": "SUK",
      "SUB_INVENTORIES": [
        {
          "NAME": "RAWWIP",
          "LOCATORS": [
            {
              "NAME": "VANTAGE"
            }
          ]
        }
      ]
    },
    {
      "NAME": "SUS",
      "SUB_INVENTORIES": [
        {
          "NAME": "FG",
          "LOCATORS": [
            {
              "NAME": "FGACCESSORY"
            }
          ]
        }
      ]
    },
    {
      "NAME": "SUS",
      "SUB_INVENTORIES": [
        {
          "NAME": "FG",
          "LOCATORS": [
            {
              "NAME": "FGPB"
            }
          ]
        }
      ]
    },
    {
      "NAME": "SUS",
      "SUB_INVENTORIES": [
        {
          "NAME": "RAWWIP",
          "LOCATORS": [
            {
              "NAME": "FLOOR"
            }
          ]
        }
      ]
    },
    {
      "NAME": "SUS",
      "SUB_INVENTORIES": [
        {
          "NAME": "RAWWIP",
          "LOCATORS": [
            {
              "NAME": "VANTAGE"
            }
          ]
        }
      ]
    }
  ]
}

预期输出：（我需要将所有 hub 和所有 sub_inventories 同名分组）

 {
   "PART_NUMBER": "501-239",
   "HUBS": [
     {
       "NAME": "SUK",
       "SUB_INVENTORIES": [
         {
           "NAME": "FG",
           "LOCATORS": [
             {
               "NAME": "FGACCESSORY"
             },
             {
               "NAME": "FGPB"
             }
           ]
         },
         {
           "NAME": "RAWWIP",
           "LOCATORS": [
             {
               "NAME": "FLOOR"
             },
             {
               "NAME": "VANTAGE"
             }
           ]
         }
       ]
     },
     {
       "NAME": "SUS",
       "SUB_INVENTORIES": [
         {
           "NAME": "FG",
           "LOCATORS": [
             {
               "NAME": "FGACCESSORY"
             },
             {
               "NAME": "FGPB"
             }
           ]
         },
         {
           "NAME": "RAWWIP",
           "LOCATORS": [
             {
               "NAME": "FLOOR"
             },
             {
               "NAME": "VANTAGE"
             }
           ]
         }
       ]
     }
   ]
 }

请给我一些建议！

【问题讨论】：

标签： dataweave mulesoft

【解决方案1】：

试试这个：

%dw 2.0
output application/dw
---
do {
    var hubs = payload.HUBS groupBy $.NAME
    ---
    {
        PART_NUMBER: payload.PART_NUMBER,
        HUBS: (
            hubs mapObject do {
                var subs = flatten($.*SUB_INVENTORIES) groupBy $.NAME
                ---
                {($$): {
                    NAME: $$,
                    SUB_INVENTORIES: (
                        subs mapObject do {
                            var locs = flatten($.*LOCATORS)
                            ---
                            {($$): {
                                NAME: $$,
                                LOCATORS: locs
                            }}
                        }
                    ) pluck $
                }}
            }
        ) pluck $
    }
}

与我所做的相比，必须有更好的方法来做到这一点——即我不喜欢将同一个表达式（大多数情况下）嵌套三次。我只是还看不到它，我在这上面花了足够的时间:)。

希望对你有帮助。

【讨论】：