我需要在一个选择查询中找到 RECENT、MAX、SUM 作为数据集值加入两个表

Question

我有两个表“收据表：”和“人员表：”
我需要找到这些值的结果集 SUM 金额，截至今天支付的 MAXIMUM amt，截至今天 MAXIMUM amtpaid_DATE， RECENT amt pay for today, RECENT amt paid_DATE 截至今天。

下面是 Tabluler 格式。

收据表：

ReceiptID   Receipt_Date    AmountPaid  PersonID
R001    1/1/2011    $50     P003
R002    1/2/2011    $20.20  P001
R003    1/2/2011    $35     P005
R004    1/4/2011    $17     P002
R005    1/10/2011   $89.20  P003
R006    1/11/2011   $10     P001
R007    1/11/2011   $9.15   P007
R008    1/12/2011   $5.45   P002
R009    1/20/2011   $65     P006
R010    1/23/2011   $20     P004
R011    1/29/2011   $10     P003

人表：

PersonID    PersonName
P001    A_person
P002    B_person
P003    C_person
P004    D_person
P005    E_person
P006    F_person
P007    G_person
P008    H_person

输出结果：

PersonID    PersonName  Sum(Amtpaid)    RECENT(AmountPaid)  RECENT(Amtpaid_ReceiptDate) Max (Amt Receipt_paid as of today)  Max (amt receipt paid Date as of today)
P001    A_Person    $30.20  $10     1/11/2011   $20.20  1/2/2011
P002    B_person    $22.45  $5.45   1/12/2011   $17     1/4/2011
P003    C_person    $149.20     $10     1/29/2011   $89.20  1/10/2011
P004    D_person    $20     $20     1/23/2011   $20     1/23/2011
P005    E_person    $35     $35     1/2/2011    $35     1/2/2011
P006    F_person    $65     $65     1/20/2011   $65     1/20/2011
P007    G_person    $9.15   $9.15   1/11/2011   $9.15   1/11/2011

Answer 1

我不在可以测试此代码的计算机上，但也许您可以试试这个：

;WITH Receipts AS
(
    SELECT  *, 
            SUM(AmountPaid) OVER(PARTITION BY PersonID) SumAmount, 
            MAX(AmountPaid) OVER(PARTITION BY PersonID) MaxAmount,
            MAX(Receipt_Date) OVER(PARTITION BY PersonID) RecentPaidDate
    FROM ReceiptTable
)

SELECT  P.PersonId, P.PersonName, 
        MIN(SumAmount) SumAmount,
        MIN(CASE WHEN Receipt_Date = RecentPaidDate THEN AmountPaid END) RecentAmountPaid,
        MIN(RecentPaidDate) RecentPaidDate,
        MIN(MaxAmount) MaxAmount,
        MIN(CASE WHEN AmountPaid = MaxAmount THEN Receipt_Date END) MaxAmountReceiptDate
FROM PersonTable P
JOIN Receipts R
ON R.PersonId = P.PersonID
GROUP BY P.PersonId, P.PersonName

无论如何，如果您之前使用该代码，您应该知道它返回MINReceiptDate，以防重复MaxAmountPaid（意味着它有2条相同金额的记录和MaxAmountPaid）。

Answer 2

类似...

select 
p.PersonID,
p.PersonName,
sum(AmountPaid),
(select top 1 AmountPaid from RECEIPT where PersonID = p.PersonID Order By Receipt_Date Desc) AS recentPaidAmt,
(select top 1 Receipt_Date from RECEIPT where PersonID = p.PersonID Order By Receipt_Date Desc) AS recentPaidDate,
(select top 1 AmountPaid from RECEIPT where PersonID = p.PersonID Order By AmountPaid Desc) AS maxRecentPaidAmt,
(select top 1 Receipt_Date from RECEIPT where PersonID = p.PersonID Order By AmountPaid Desc) AS maxRecentPaidDate
from RECEIPT r, PERSON p 
where p.PersonID = r.PersonID
group by p.PersonID

Answer 3

试试这个：

Select personId, PersonName,
    Sum(r.amountPaid) TotalPaid,
    Max(m.amountPaid) MaxPaid,
    Max(m.Receipt_Date) MaxpaidDate,
    Max(x.amountPaid) recentPaid,
    Max(x.Receipt_Date) recentPaidDate

From Person p
   Left Join receipt r on r.PersonId = p.personId
   Left join receipt x 
       On x.personId = p.personId
           And x.Receipt_Date  =
              (Select Max(Receipt_Date)
               From Receipt
               Where personId = x.PersonId)
   Left join receipt m 
       On m.ReceiptId = 
         (Select Max(ReceiptId)
          From Receipt
           Where personId = m.PersonId 
              And amountPaid = 
                 (Select Max(amountPaid)
                  From Receipt
                  Where personId = m.PersonId))
Group By personId, PersonName