【发布时间】：2018-04-20 13:49:33
【问题描述】：
我知道这个主题已经涵盖了类似的问题，我已经查看了答案，但不幸的是我无法弄清楚如何应用到这个查询。 我知道将 'pe.short_name' 添加到 GROUP BY 也不是处理此问题的最佳方法。 任何建议都非常感谢..
列“pe.short_name”在选择列表中无效，因为它包含 在聚合函数或 GROUP BY 子句中。`
SELECT CASE
WHEN SUBSTRING(s.description, 13, 1) = '.'
THEN LEFT(s.description, 17)
ELSE LEFT(s.description, 12)
END WBSCode
,pe.short_name
,pn.description ProjectName
,(
SELECT description
FROM structure
WHERE structure_code = pe.code346
) ActivePortfolio
,CASE
WHEN ast.Description = 'WAIO'
THEN anc.Description
ELSE site.Description
END SiteFunction
,CASE
WHEN SUBSTRING(jv.description, 5, 1) = ' '
THEN LEFT(jv.description, 4)
WHEN SUBSTRING(jv.description, 7, 1) = ' '
THEN LEFT(jv.description, 6)
ELSE jv.Description
END AS JointVenture
,(
SELECT description
FROM structure
WHERE structure_code = pe.code79
) AssetClassification
,(
SELECT description
FROM structure
WHERE structure_code = pe.code390
) InvestmentSize
,(
SELECT RIGHT(import_code, 6)
FROM structure
WHERE structure_code = pe.code79
) AssetClassCode
,CAST(p.period_start AS DATE) Period_Start
,SUM(CASE
WHEN be.currency_code = 'AUD'
AND @Currency = 'AUD'
THEN be.amount
WHEN be.currency_code = 'USD'
AND @Currency = 'USD'
THEN be.amount
WHEN be.currency_code = 'AUD'
AND @Currency = 'USD'
THEN be.amount * ip.pfn_exch_rate_on_date(p.period_start, be.currency_code)
WHEN be.currency_code = 'USD'
AND @Currency = 'AUD'
THEN be.amount * (ip.pfn_exch_rate_on_date(p.period_start, be.currency_code) / ip.pfn_exch_rate_on_date(p.period_start, 'AUD'))
END) Amount
FROM fm_budget_entry be
JOIN fm_period p ON be.period_id = p.period_id
JOIN fm_budget_line bl ON be.line_id = bl.line_id
AND bl.version_id = @FinancialVersion
JOIN fm_budget_line_attrib la ON la.line_id = bl.line_id
AND la.line_attrib_code = 'Wbs138'
JOIN structure s ON la.line_attrib_value = s.structure_code
JOIN fm_account fa ON bl.account_code = fa.account_code
JOIN planning_entity pe ON pe.planning_code = bl.structure_code
JOIN structure ast ON ast.structure_code = pe.code713
AND ast.Description IN (@Assets)
JOIN structure pn ON pn.structure_code = pe.planning_code
LEFT JOIN structure site ON site.structure_code = pe.code37
LEFT JOIN structure_tree tr ON tr.dsc_code = pe.planning_code
AND tr.anc_Depth = 5
LEFT JOIN structure anc ON anc.structure_code = tr.anc_code
LEFT JOIN fm_version v ON v.version_id = bl.version_id
LEFT JOIN structure pc ON pc.structure_code = s.father_code
LEFT JOIN structure jv ON pc.father_code = jv.structure_code
AND jv.father_code <> 'Wbs138Root'
WHERE fa.account_type_code IN (@FundingType)
AND p.period_id BETWEEN @StartDate
AND @FinishDate
AND pe.code346 IN (@ActivePortfolio)
GROUP BY CASE
WHEN SUBSTRING(s.description, 13, 1) = '.'
THEN LEFT(s.description, 17)
ELSE LEFT(s.description, 12)
END
,pn.description
,pe.code346
,CASE
WHEN ast.Description = 'WAIO'
THEN anc.Description
ELSE site.Description
END
,CASE
WHEN SUBSTRING(jv.description, 5, 1) = ' '
THEN LEFT(jv.description, 4)
WHEN SUBSTRING(jv.description, 7, 1) = ' '
THEN LEFT(jv.description, 6)
ELSE jv.Description
END
,pe.code79
,pe.code390
,CAST(p.period_start AS DATE)
ORDER BY 1
,CAST(p.period_start AS DATE)
【问题讨论】：
-
好吧！这是一个可怕的查询！
-
在 group by 子句后面添加
pe.short_name字段。 -
这个查询太可怕了。我讨厌成为必须主宰它的灵魂。对于您的问题，（a）通过将
pe.short_name包装在 SUM() 或其他一些聚合函数中来聚合它，（b）将它添加到 group-by （您说您不想要）在这种情况下您有每个不同值的单独行，或 (c) 一起省略该字段。没有看到您的数据，很难告诉您什么是最好的。 -
我很高兴不只是我这么想......我对 SQL 非常陌生，并且负责维护一堆报告......我没有写过这些报告。 ..我必须承认我正在为这些查询而苦苦挣扎..>我认为这只是我刚接触 SQL...非常感谢您的建议！
-
我敢打赌，您在该错误消息中遗漏了一个 not。