【发布时间】:2015-04-06 22:43:32
【问题描述】:
我有一个从 VAR Class 继承的抽象类操作,然后所有操作派生类(out,sleep,Add)都从操作类继承。 FSM 类也继承自 Var,所以我希望在我的程序中有一个 VAR 类的实例。
我正在尝试将向量
每次我们通过类操作调用VAR中的exist函数时,它都会返回它不退出,因为它是空的!我该如何克服呢?
#include <iostream>
#include <string>
#include <vector>
#include <fstream>
using namespace std;
class VAR
{
public:
vector<pair<string, int>> var;
VAR()
{
cout << "created VAR" << endl;
}
~VAR(){ cout << "Destrioed VAR" << endl; }
void createVar(string x,int y)
{
pair<string, int>t;
t.first = x;
t.second = y;
var.push_back(t);
}
int getVarValue(string x)
{
for (int i = 0; i<var.size(); i++)
{
if (var[i].first == x)
{
return var[i].second;
}
}
}
void setVarValue(string& x, int y)
{
for (int i = 0; i<var.size(); i++)
{
if (var[i].first == x)
{
var[i].second = y;
i = var.size();
}
}
}
bool exits(string& name)
{
for (int i = 0; i<var.size(); i++)
{
if (var[i].first == name)
return true;
}
return false;
}
};
class operations : virtual public VAR
{
public:
operations()
{
cout << "operations created" << endl;
}
~operations()
{
cout << "operations Destroied" << endl;
}
void virtual excute() = 0;
};
class Out :public virtual operations
{
public:
string s;
Out(string xx = "") :s(xx)
{
cout << "Out created" << endl;
}
~Out()
{
cout << "Out Destroied" << endl;
}
void virtual excute()
{
cout << "out Class" << endl;
if (exits(s))
cout<<"it never reach here, WHY !"<<endl;
}
};
class Add :public virtual operations
{
public:
string s;
Add(string ss = "") :s(ss)
{
cout << "ADD created" << endl;
}
~Add()
{
cout << "Add Destroied" << endl;
}
void virtual excute()
{
string ex1 = s.substr(s.find('=') + 1, s.find('+')), ex2 = s.substr(s.find('+') + 1);
if (exits(ex1))
cout<<"it never reach here, WHY !"<<endl;
else
result = atoi(ex1.c_str());
if (exits(ex2))
cout<<"it never reach here, WHY !"<<endl;
}
};
class state
{
public:
vector<operations*> instructionList;
string name;
void exec_all()
{
for (int x = 0; x < instructionList.size(); x++)
instructionList[x]->excute();
}
};
class transition
{
public:
vector < pair<state, vector<pair<state, int>>>> trans;
static int currentState;
};
class FSM :public virtual VAR, public virtual transition
{
public:
FSM()
{
cout << "FSM" << endl;
}
void intialize()
{
createVar("X", 1);
createVar("Y", 5);
}
};
void main()
{
FSM x;
pair<state, vector<pair<state, int>>> p1;
pair<state, int>p2;
x.intialize();
p2.first.name = "b";
p2.second = 3;
p1.first.name = "a";
p1.second.push_back(p2);
x.trans.push_back(p1);
x.trans[0].first.instructionList.push_back(new Add("X=X+Y"));
x.trans[0].first.instructionList.push_back(new Out("X"));
x.trans[0].first.exec_all();//wrong output cause exist() returns false
}
【问题讨论】:
-
TL;博士!请创建一个Minimal, Complete, and Verifiable Example 来展示您想要的内容。
-
Wait没有像其他类一样继承的任何原因? -
因为wait不需要变量,即使我们让它继承自VAR也没关系。
-
听起来你误会了什么。您没有一个
VAR实例 - 从VAR继承的每个实例都是一个VAR实例。他们都有自己独特的var成员;都与x中的不同。 -
如何使用继承来联合这些变量?
标签: c++ class inheritance