您还没有发布 RDBMS,或者表的名称,或者 Job Role 表应该做什么......但无论如何我都会对此进行尝试。我正在使用递归 CTE 来生成日期列表,但使用 Date 表对您来说会好得多,而且我什至不知道您的 RDBMS 是否会支持这一点。我还在下面发布了一个表格变量的语法,它填充了模仿您的样本的数据。
最终的输出自然需要进行定制以完成您需要做的任何事情。但是,这确实会向您显示多个员工休假的每个日期的列表。如有必要,向第二个 JOIN 或 WHERE 子句添加额外条件以过滤其他内容(如 JobRole)。
-- Code originally from http://smehrozalam.wordpress.com/2009/06/09/t-sql-using-common-table-expressions-cte-to-generate-sequences/
-- Define start and end limits
DECLARE @todate DATETIME, @fromdate DATETIME
SELECT @fromdate='2014-01-01', @todate=GETDATE()-1
DECLARE @TimeOff TABLE (StartDate DATETIME, EndDate DATETIME, EmployeeID INT)
INSERT INTO @TimeOff (StartDate, EndDate, EmployeeID)
SELECT '1/1/2014', '1/7/2014', 7 UNION
SELECT '2/1/2014', '2/7/2014', 7 UNION
SELECT '3/3/2014', '3/9/2014', 7 UNION
SELECT '2/5/2014', '2/6/2014', 8
;WITH DateSequence( Date ) AS -- this will list all dates. Use this if you don't have a date table
(
SELECT @fromdate as Date
UNION ALL
SELECT DATEADD(DAY, 1, Date)
FROM DateSequence
WHERE Date < @todate
)
--select result
SELECT DateSequence.Date, TimeOffA.StartDate, TimeOffB.EndDate, TimeOffA.EmployeeID
FROM
DateSequence -- a full list of all possible dates
INNER JOIN
@TimeOff TimeOffA ON -- all dates when an employee is on vacation -- replace this with your actual table's name
DateSequence.Date BETWEEN TimeOffA.StartDate AND TimeOffA.EndDate
INNER JOIN
@TimeOff TimeOffB ON -- all dates when an employee who is NOT employee A is on vacation -- replace this with your actual table's name
DateSequence.Date BETWEEN TimeOffB.StartDate AND TimeOffB.EndDate AND
TimeOffA.EmployeeID <> TimeOffB.EmployeeID
option (MaxRecursion 2000)