我该如何解决？ “不支持的操作数类型”答案

【问题标题】：How do i fix this? "Unsupported operand type(s)"我该如何解决？ “不支持的操作数类型”
【发布时间】：2019-08-01 18:14:31
【问题描述】：

import random 
athletes = ["John","Mike","Jack","Steve","Bob"]
judges = ["Judge1","Judge2","Judge3"]
numbers = ["1","2","3","4","5","6","7","8","9","10"]
def score():
  random.shuffle(numbers)
  judge_scores = numbers[0] + numbers[1] + numbers[2]
  final = int(judge_scores)
  final_2 = sum(final)
  print(final_2)


i = 0
while i <= 4:
    athlete = athletes[i]
    print(athlete + " scored:")
    score()
    i += 1
    if i > 4:
        break

我试图让这段代码返回评委为每个运动员给出的随机分数的总和，但我遇到了一个错误，提示

int 对象不可迭代。

我稍微改变了一下，但没有运气，这是我认为最接近的原始代码：

import random 
athletes = ["John","Mike","Jack","Steve","Bob"]
judges = ["Judge1","Judge2","Judge3"]
numbers = ["1","2","3","4","5","6","7","8","9","10"]
def score():
  random.shuffle(numbers)
  judge_scores = numbers[0] + numbers[1] + numbers[2]
  final = sum(judge_scores)
  print(final)


i = 0
while i <= 4:
    athlete = athletes[i]
    print(athlete + " scored:")
    score()
    i += 1
    if i > 4:
        break

我再次遇到错误。这次我得到这个错误：

TypeError: +: 'int' 和 'str' 的操作数类型不受支持

【问题讨论】：

我很确定您的代码 sn-p 不完整，并且您在某处为运动员分配了号码
您的numbers 是字符串。使用整数。

标签： python

【解决方案1】：

您可以像这样将数字列表中的字符串值更改为 int：

import random 
athletes = ["John","Mike","Jack","Steve","Bob"]
judges = ["Judge1","Judge2","Judge3"]
numbers = [1,2,3,4,5,6,7,8,9,10]
def score():
  random.shuffle(numbers)
  judge_scores = numbers[0] + numbers[1] + numbers[2]

  print(judge_scores)


i = 0
while i <= 4:
    athlete = athletes[i]
    print(athlete + " scored:")
    score()
    i += 1
    if i > 4:
        break

或者你可以使用

import random 
athletes = ["John","Mike","Jack","Steve","Bob"]
judges = ["Judge1","Judge2","Judge3"]
numbers = ["1","2","3","4","5","6","7","8","9","10"]
def score():
  random.shuffle(numbers)
  judge_scores = int(numbers[0]) + int(numbers[1]) + int(numbers[2])

  print(judge_scores)


i = 0
while i <= 4:
    athlete = athletes[i]
    print(athlete + " scored:")
    score()
    i += 1
    if i > 4:
        break

【讨论】：

好的，现在可以了，感谢您的帮助。我真的应该早点注意到，有点愚蠢的错误。
我的快乐

【解决方案2】：

您是否有一个带有数字的列表，因为 str 尝试将数字更改为数字 = [1,2,3,4,5,6,7,8,9,10]

【讨论】：

【解决方案3】：

判断分数在字符串和sum适用于int类型，你需要先将stirng转换为int然后进行求和操作

import random 
athletes = ["John","Mike","Jack","Steve","Bob"]
judges = ["Judge1","Judge2","Judge3"]
numbers = ["1","2","3","4","5","6","7","8","9","10"]
def score():
  random.shuffle(numbers)
  judge_scores = [numbers[0] , numbers[1] , numbers[2]]
  final = sum(map(int,judge_scores))
  print(final)


i = 0
while i <= 4:
    athlete = athletes[i]
    print(athlete + " scored:")
    score()
    i += 1
    if i > 4:
        break

【讨论】：

【解决方案4】：

sum 接受一个可迭代对象并将其值求和。在您的情况下，numbers 包含字符串，因此它将字符串连接起来：('2', '5', '7') 转到'257'。在[1,2,...] 中更改您的numbers 列表，一切都会好起来的。

另外，你可以输入

numbers = list(range(10))

【讨论】：