“井字游戏”Touch Lua 随机方块被填满？

Question

所以我最近在 Touch Lua 上购买了绘图库！我已经开始尝试制作一个简单的井字游戏。我正在使用他们用来检测 NumPad 默认程序上的点击的简单设置，所以按钮应该可以工作。

问题在于，当您点击一个正方形时，O 会填充到看似随机的正方形中，有时会超过 1 个，最多可能会填充 4 个以上的正方形。

我怀疑问题出在 Picked 函数上，它将标题设置为 X/O，然后更新板子。

local Turn = nil
local Move = "O"
local Mode = nil

::ModePick::
print("1 player mode? (y/n)")
local plrs = io.read()
if plrs == "y" then
   Mode = 1
   goto TurnChoice
elseif plrs == "n" then
   Mode = 2
   goto Game
else
   goto ModePick
end

::TurnChoice::
 print("Would you like to go first? (Be O) (y/n)")
do
   local pick = io.read()
   if pick == "y" then
       Turn = 1
   elseif pick == "n" then
      Turn = 2
   else
      goto TurnChoice
   end
end

::Game::

local Buttons = {}

draw.setscreen(1)
draw.settitle("Tic Tac Toe")
draw.clear()
width, height = draw.getport()

function Picked(b)
   for i,v in pairs(Buttons) do
      if v == b then
         b.title = Move
         UpdateBoard()
      end
   end
   --Fill in X/O details
   --Detect if there's a tic/tac/toe
   --Set winning screen
   if Move == "O" then
       --Compute Move (1 player)
       --Move = "X" (2 player)
   else
      Move = "O"
   end
end

function DrawButton(b)
   draw.setfont('Helvetica', 50)
   draw.setlinestyle(2, 'butt')
   local x1, y1 = b.x, b.y
   local x2, y2 = x1+b.width, y1+b.height
   draw.rect(x1, y1, x2, y2, b.color)

   local w, h = draw.stringsize(b.title)
   local x = b.x + (b.width - w)/2
   local y = b.y + (b.height - h)/2
   draw.string(b.title, x, y, draw.black)
   return b
end

function Button(x, y, x2, y2, title, color, action)
   local action = action or function() end
   local button = {x = x, y = y, width = x2, height = y2, color = color, title = title, action = action}
   table.insert(Buttons, button)
   return button
end

function LookUpButton(x, y)
   for i = 1, #Buttons do
      local b = Buttons[i]
      if x > b.x and x < b.x+b.width and y > b.y and y < b.y+b.height then
         return b
      end
   end
   return nil
end

function TouchBegan(x, y)
   local b = LookUpButton(x, y)
   if b then
      b.action(b)
   end
end

function TouchMoved(x, y)
end

function TouchEnded(x, y)
end

draw.tracktouches(TouchBegan, TouchMoved, TouchEnded)


function CreateButton(x,y,x2,y2,txt,col,func)
   return DrawButton(Button(x, y, x2, y2, txt, col, func))
end

function UpdateBoard()
   draw.clear()
   for i = 1,3 do
        for ii = 1,3 do
             CreateButton(100 * (ii - 1) + 7.5, 100 * (i - 1) + 75, 100, 100,  Buttons[i + ii].title, draw.blue, Picked)
      end
   end
end

for i = 1,3 do
   for ii = 1,3 do
      CreateButton(100 * (ii - 1) + 7.5, 100 * (i - 1) + 75, 100, 100,  "", draw.blue, Picked)
   end
end

while true do
   draw.doevents()
   sleep(1)
end

注意：很抱歉，如果缩进出现错误，我将所有这些代码都粘贴到了我的 iPod 上，所以我不得不手动在每行开始输入 4 个空格。

如果有人可以帮助我解决我遇到的这个小挫折，我很乐意帮助，如果我缺少任何东西，我很乐意在 cmets 中回复编辑它：D

编辑：我已经修改了一些代码来修复表格如何不断获得新按钮，这是我现在拥有的代码，同样的问题，按钮被添加到错误的位置（现在被删除）：

function Button(x, y, x2, y2, title, color, action, prev)
   local action = action or function() end
   local button = {x = x, y = y, width = x2, height = y2, color = color, title = title, action = action}
   if prev then
      for i,v in pairs(Buttons) do
         if v == prev then
            table.remove(Buttons, i)
         end
      end
   end
   table.insert(Buttons, button)
   return button
end

function CreateButton(x,y,x2,y2,txt,col,func, prev)
   return DrawButton(Button(x, y, x2, y2, txt, col, func, prev))
end

function UpdateBoard()
   draw.clear()
   for i = 1,3 do
      for ii = 1,3 do
         CreateButton(100 * (ii - 1) + 7.5, 100 * (i - 1) + 75, 100, 100,  Buttons[i + ii].title, draw.blue, Picked, Buttons[i + ii])
      end
   end
end

编辑：感谢 Etan，我修复了 UpdateBoard，方块仍然是随机的：

function UpdateBoard()
   draw.clear()
   local n = 1
   for i = 1,3 do
      for ii = 1,3 do
         CreateButton(100 * (ii - 1) + 7.5, 100 * (i - 1) + 75, 100, 100,  Buttons[n].title, draw.blue, Picked, Buttons[n])
         n = n + 1
      end
   end
end

Answer 1

我已经有一段时间没有发布完成的代码了，但这就是它的样子：

function UpdateBoard(ended)
   local ended = ended or false
   local Act = nil
   if ended == true then
      Act = function() end
   else
      Act = Picked
   end
   draw.clear()
   local Buttons2 = {}
   for i,v in pairs(Buttons) do
      Buttons2[i] = v
   end
   Buttons = {}
   local n = 1
   for i = 1,3 do
      for ii = 1,3 do
         CreateButton(100 * (ii - 1) + 7.5, 100 * (i - 1) + 75, 100, 100,  Buttons2[n].title, draw.blue, Act, Buttons2[n], i, ii)
         n = n + 1
      end
   end
   OpenButtons = {}
   ClosedButtons = {}
   for i,v in pairs(Buttons) do
      if v.title == "" then
         table.insert(OpenButtons, v)
      else
         table.insert(ClosedButtons, v)
      end
   end
end

这个问题可能看起来有点复杂，但这是多个其他事情之后的代码。

您应该注意的主要区别在于，它重新创建了按钮表，因此它不会重新计算新按钮，并且它使用 n 来计数，而不是使用 i 和 ii。