【问题标题】:Swift Codable - How to encode custom arraySwift Codable - 如何编码自定义数组
【发布时间】:2020-05-30 12:44:21
【问题描述】:

这是我的 JSON 案例

      {
                 "image_id": 11101,
                 "image_source_id": 9,
                 "image_author": "",
                 "image_copyright": "",
                 "image_format_list": [{
                         "image_format": {
                             "image_url": "https://static.musixmatch.com/images-storage/mxmimages/1/0/1/1/1/11101_2.jpg",
                             "image_format_id": 2,
                             "width": 150,
                             "height": 150
                         }
                     },
                     {
                         "image_format": {
                             "image_url": "https://static.musixmatch.com/images-storage/mxmimages/1/0/1/1/1/11101_16.jpg",
                             "image_format_id": 16,
                             "width": 451,
                             "height": 500
                         }
                     }
                 ]
             }

我在两个不同的类中正确解码了我的自定义对象:MXMImage 和 MXMImageFormat。 但我不知道如何重新编码我的对象以重建相同的 JSON

这是我的代码:

    struct MXMImage : Decodable, Encodable, Equatable {
        let imageId: Int
        let imageSourceId: Int
        let imageAuthor: String?
        let imageCopyright: String?
        let imageFormatList: [MXMImageFormat]?

        enum CodingKeys: String, Swift.CodingKey {
            case imageId
            case imageSourceId
            case imageAuthor
            case imageCopyright
            case imageFormatList

            enum ImageFormatListKey: String, CodingKey {
                case imageFormat
            }
        }

        public init(from decoder: Decoder) throws {
            let container = try decoder.container(keyedBy: CodingKeys.self)
            imageId = try (container.decodeIfPresent(Int.self, forKey: .imageId) ?? 0)
            imageSourceId = try (container.decodeIfPresent(Int.self, forKey: .imageSourceId) ?? 0)
            imageAuthor = try? container.decodeIfPresent(String.self, forKey: .imageAuthor)
            imageCopyright = try? container.decodeIfPresent(String.self, forKey: .imageCopyright)

            var imagesFormatListContainer = try container.nestedUnkeyedContainer(forKey: .imageFormatList)
            var imagesList:[MXMImageFormat] = []
            while !imagesFormatListContainer.isAtEnd {
                let imageFormatContainer = try imagesFormatListContainer.nestedContainer(keyedBy: CodingKeys.ImageFormatListKey.self)
                let imageFormat = try? imageFormatContainer.decode(MXMImageFormat.self, forKey: .imageFormat)
                if let imageFormat = imageFormat {
                    imagesList.append(imageFormat)
                }
            }
            self.imageFormatList = imagesList
        }

        public func encode(to encoder: Encoder) throws {
            var container = encoder.container(keyedBy: CodingKeys.self)

            try container.encodeIfPresent(imageId, forKey: .imageId)
            try container.encodeIfPresent(imageSourceId, forKey: .imageSourceId)
            try container.encodeIfPresent(imageAuthor, forKey: .imageAuthor)
            try container.encodeIfPresent(imageCopyright, forKey: .imageCopyright)

            var imageContainer = container.nestedUnkeyedContainer(forKey: .imageFormatList)
            try imageFormatList?.forEach { imgFormat in
                var nested = imageContainer.nestedContainer(keyedBy: CodingKeys.ImageFormatListKey.self)
                let data = try imgFormat.encoded()
                try nested.encode(data, forKey: .imageFormat)

            }
        }
    }

特别是,我不知道如何在键 image_format 内重新缩进我的 MXMImageFormat 对象,然后对自定义数组进行编码。有可能这样做吗?提前致谢

【问题讨论】:

标签: ios json swift codable


【解决方案1】:

您可以解码/编码 [[String:MXMImageFormat]] 数组并映射它,而不是 nestedContainers

struct MXMImage : Codable, Equatable {
    let imageId: Int
    let imageSourceId: Int
    let imageAuthor: String?
    let imageCopyright: String?
    let imageFormatList: [MXMImageFormat]?

    private enum CodingKeys : String, CodingKey { case imageId,  imageSourceId,  imageAuthor, imageCopyright, imageFormatList}

    public init(from decoder: Decoder) throws {
        let container = try decoder.container(keyedBy: CodingKeys.self)
        imageId = try container.decode(Int.self, forKey: .imageId)
        imageSourceId = try container.decode(Int.self, forKey: .imageSourceId)
        imageAuthor = try container.decodeIfPresent(String.self, forKey: .imageAuthor)
        imageCopyright = try container.decodeIfPresent(String.self, forKey: .imageCopyright)
        if let imageFormatListData = try container.decodeIfPresent([[String:MXMImageFormat]].self, forKey: .imageFormatList) {
            imageFormatList = imageFormatListData.compactMap{$0["image_format"]}
        } else {
            imageFormatList = nil
        }
    }

    public func encode(to encoder: Encoder) throws {
        var container = encoder.container(keyedBy: CodingKeys.self)
        try container.encode(imageId, forKey: .imageId)
        try container.encode(imageSourceId, forKey: .imageSourceId)
        try container.encodeIfPresent(imageAuthor, forKey: .imageAuthor)
        try container.encodeIfPresent(imageCopyright, forKey: .imageCopyright)
        if let imageFormatListData = imageFormatList {
            try container.encode(imageFormatListData.map{["image_format":$0]}, forKey: .imageFormatList)
        }
    }
}

struct MXMImageFormat : Codable, Equatable {
    let imageUrl : URL
    let imageFormatId, width, height : Int
}

【讨论】:

    【解决方案2】:

    假设MXMImageFormat是这样的:

    struct MXMImageFormat : Codable {
        let imageUrl: String
        let imageFormatId: Int
        let width: Int
        let height: Int
    }
    

    我认为你想多了。你可以这样做:

    try imageFormatList?.forEach { imgFormat in
        var nested = imageContainer.nestedContainer(keyedBy: CodingKeys.ImageFormatListKey.self)
        try nested.encode(imgFormat, forKey: .imageFormat)
    }
    

    因为encode 接受任何Encodable,包括imgFormat。您实际上不需要先转换为 Data(至少这就是您似乎试图这样做的原因)。

    一些测试代码:

    let json = """
    {
       "image_id": 11101,
       "image_source_id": 9,
       "image_author": "",
       "image_copyright": "",
       "image_format_list": [{
               "image_format": {
                   "image_url": "https://static.musixmatch.com/images-storage/mxmimages/1/0/1/1/1/11101_2.jpg",
                   "image_format_id": 2,
                   "width": 150,
                   "height": 150
               }
           },
           {
               "image_format": {
                   "image_url": "https://static.musixmatch.com/images-storage/mxmimages/1/0/1/1/1/11101_16.jpg",
                   "image_format_id": 16,
                   "width": 451,
                   "height": 500
               }
           }
       ]
    }
    """.data(using: .utf8)!
    
    let decoder = JSONDecoder()
    decoder.keyDecodingStrategy = .convertFromSnakeCase
    let model = try! decoder.decode(MXMImage.self, from: json)
    let encoder = JSONEncoder()
    encoder.keyEncodingStrategy = .convertToSnakeCase
    let string = String(data: try! encoder.encode(model), encoding: .utf8)!
    print(string) // this should be the same JSON as the one in the string literal
    

    另请注意,在encode 中,您不必在此处使用try?

    while !imagesFormatListContainer.isAtEnd {
        let imageFormatContainer = try imagesFormatListContainer.nestedContainer(keyedBy: CodingKeys.ImageFormatListKey.self)
        // here vvvvvvv
        let imageFormat = try? imageFormatContainer.decode(MXMImageFormat.self, forKey: .imageFormat)
        if let imageFormat = imageFormat {
            imagesList.append(imageFormat)
        }
    }
    

    【讨论】:

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