用 PowerShell 查找和替换 href 值？答案

【问题标题】：Find and replace a href value with PowerShell?用 PowerShell 查找和替换 href 值？
【发布时间】：2021-11-03 23:34:38
【问题描述】：

我有一个包含大量链接的 HTML 文件。它们的格式为 http:/oldsite/showFile.asp?doc=1234&amp;lib=lib1 我想用 http://newsite/?lib=lib1&doc=1234

（1234和lib1是可变的）

你知道怎么做吗？

谢谢 P

【问题讨论】：

标签： powershell

【解决方案1】：

我不认为你的例子是正确的。

http:/oldsite/showFile.asp?doc=1234&amp;lib=lib1 应该是
http:/oldsite/showFile.asp?doc=1234&lib=lib1

和

http://newsite/?lib=lib1&doc=1234 应该是http://newsite?lib=lib1&doc=1234

要对这些进行替换，您可以这样做

'http:/oldsite/showFile.asp?doc=1234&lib=lib1' -replace 'http:/oldsite/showFile\.asp\?(doc=\d+)&(lib=\w+)', 'http://newsite?$2&$1'

返回http://newsite?lib=lib1&doc=1234

要在文件中替换这些，您可以使用：

(Get-Content -Path 'X:\TheHtmlFile.html' -Raw) -replace 'http:/oldsite/showFile\.asp\?(doc=\d+)&(lib=\w+)', 'http://newsite?$2&$1' |
 Set-Content -Path 'X:\TheNewHtmlFile.html'

正则表达式详细信息：

http:/oldsite/showFile        Match the characters “http:/oldsite/showFile” literally
\.                            Match the character “.” literally
asp                           Match the characters “asp” literally
\?                            Match the character “?” literally
(                             Match the regular expression below and capture its match into backreference number 1
   doc=                       Match the characters “doc=” literally
   \d                         Match a single digit 0..9
      +                       Between one and unlimited times, as many times as possible, giving back as needed (greedy)
)                            
&                             Match the character “&” literally
(                             Match the regular expression below and capture its match into backreference number 2
   lib=                       Match the characters “lib=” literally
   \w                         Match a single character that is a “word character” (letters, digits, etc.)
      +                       Between one and unlimited times, as many times as possible, giving back as needed (greedy)
)

【讨论】：

非常感谢您的详细解释。

【解决方案2】：

读入文件，遍历每一行并将旧值替换为新值，将输出发送到新文件：

gc file.html | % { $_.Replace('oldsite...','newsite...') } | out-file new-file.html

【讨论】：

谢谢。我不确定如何进行替换。我认为这是我需要的正则表达式。