【发布时间】：2014-03-25 08:53:27
【问题描述】：
当我尝试使用 table.setValueAt() 粘贴到 JTable 单元格时，我粘贴的单元格仍然为空白，但 setValueAt() 似乎正在工作。另外，当我尝试从一个单元格剪切或复制时，当我想粘贴到另一个单元格时，JPopupMenu 上的粘贴选项仍然处于禁用状态。我不确定为什么。我的代码如下。
class CopyAction extends AbstractAction {
private JTable table;
public CopyAction(JTable table)
{
this.table = table;
}
@Override
public void actionPerformed(ActionEvent e)
{
int row = table.getSelectedRow();
int col = table.getSelectedColumn();
Clipboard cb = Toolkit.getDefaultToolkit().getSystemClipboard();
cb.setContents(new CellTransferable(table.getValueAt(row, col)), null);
}
}
class CutAction extends AbstractAction {
private JTable table;
public CutAction(JTable table)
{
this.table = table;
}
@Override
public void actionPerformed(ActionEvent e)
{
int row = table.getSelectedRow();
int col = table.getSelectedColumn();
Clipboard cb = Toolkit.getDefaultToolkit().getSystemClipboard();
cb.setContents(new CellTransferable(table.getValueAt(row, col)), null);
}
}
class PasteAction extends AbstractAction {
private JTable table;
private GridModel gridModel;
public PasteAction(JTable tbl, GridModel gm)
{
gridModel = gm;
table = tbl;
final Clipboard cb = Toolkit.getDefaultToolkit().getSystemClipboard();
cb.addFlavorListener(new FlavorListener() {
@Override
public void flavorsChanged(FlavorEvent e)
{
setEnabled(cb.isDataFlavorAvailable(CellTransferable.CELL_DATA_FLAVOR));
}
});
setEnabled(cb.isDataFlavorAvailable(CellTransferable.CELL_DATA_FLAVOR));
}
@Override
public void actionPerformed(ActionEvent e)
{
int row = table.getSelectedRow();
int col = table.getSelectedColumn();
Clipboard cb = Toolkit.getDefaultToolkit().getSystemClipboard();
if (cb.isDataFlavorAvailable(CellTransferable.CELL_DATA_FLAVOR))
{
try
{
Object value = cb.getData(CellTransferable.CELL_DATA_FLAVOR);
System.out.println(value);
table.setValueAt(value, row, col);
}
catch (UnsupportedFlavorException | IOException ex)
{
ex.printStackTrace();
}
}
}
}
class CellTransferable implements Transferable {
public static final DataFlavor CELL_DATA_FLAVOR = new DataFlavor(Object.class, "application/x-cell-value");
private Object cellValue;
public CellTransferable(Object cellValue) {
this.cellValue = cellValue;
}
@Override
public DataFlavor[] getTransferDataFlavors() {
return new DataFlavor[]{CELL_DATA_FLAVOR};
}
@Override
public boolean isDataFlavorSupported(DataFlavor flavor) {
return CELL_DATA_FLAVOR.equals(flavor);
}
@Override
public Object getTransferData(DataFlavor flavor) throws UnsupportedFlavorException, IOException {
if (!isDataFlavorSupported(flavor)) {
throw new UnsupportedFlavorException(flavor);
}
return cellValue;
}
}
这是我的 setValueAt() 代码
class MyModel extends AbstractTableModel
{
private String[] names = {"1", "2", "3", "4", "5" };
private String[][] values = new String[5][5];
//...other methods
public void setValueAt(Object value, int row, int col)
{
if (value instanceof Double || value instanceof Integer)
values[row][col] = value.toString();
else
{
values[row][col] = (String) value;
}
fireTableCellUpdated(row, col);
}
}
【问题讨论】：
-
GridModel在哪里？模型的setValueAt方法是这个问题的关键元素。您应该考虑创建一个runnable example which demonstrates your problem -
我有一个扩展 AbstractTableModel 的自定义 TableModel。我使用“new JTable(MyModel)”将它设置到我的表中，这是正在传递的表对象。我将删除 GridModel。
-
发布它的代码 (
GridModel)，这样我们就可以看到它在做什么以及setValueAt是如何工作的......
标签： java swing jtable copy-paste jpopupmenu