根据值的有序列表对对象数组进行排序[重复]

【问题标题】：Sort array of objects based on the ordered list of values [duplicate]根据值的有序列表对对象数组进行排序[重复]
【发布时间】：2020-06-03 17:58:31
【问题描述】：

const arr = [
{Id:"3",name: "ADMIN"},
{Id:"1",name: "SECURITY"},
{Id:"2",name: "INFORMATION_REPORTING"},
{Id: "23",name: "PAYMENTS_SERVICES"},
{Id: "344",name: "PAYMENT_HUB"},
{Id: "31",name: "RTP"},
{Id: "43",name: "PAYMENTS"},
{Id: "34",name: "GPI_ALERTS"},
{Id: "65",name: "ADMINISTRATION"}
]

我的 arr 具有此处描述的值。我想使用如下键名对 arr 重新排序，以便显示。

ADMIN
ADMINISTRATION
PAYMENTS
RTP
PAYMENTS_SERVICES
INFORMATION_REPORTING
PAYMENT_HUB
SECURITY
GPI_ALERTS

所以我想要上面显示的基于名称键的 arr。

【问题讨论】：

标签： javascript arrays

【解决方案1】：

您可以使用Array.prototype.sort() 并根据它们在orderList 中的位置（Array.prototype.indexOf()）比较arr 项目

const arr = [{Id:"3",name:"ADMIN"},{Id:"1",name:"SECURITY"},{Id:"2",name:"INFORMATION_REPORTING"},{Id:"23",name:"PAYMENTS_SERVICES"},{Id:"344",name:"PAYMENT_HUB"},{Id:"31",name:"RTP"},{Id:"43",name:"PAYMENTS"},{Id:"34",name:"GPI_ALERTS"},{Id:"65",name:"ADMINISTRATION"}],

    orderList =  ['ADMIN','ADMINISTRATION','PAYMENTS','RTP','PAYMENTS_SERVICES','INFORMATION_REPORTING','PAYMENT_HUB','SECURITY','GPI_ALERTS'],
    
    result = arr.sort(({name:nameA},{name:nameB}) =>
        !orderList.includes(nameA) ?
        1 :
        !orderList.includes(nameB) ?
        -1 :
        orderList.indexOf(nameA) - orderList.indexOf(nameB)
      )
      
console.log(result)

.as-console-wrapper{min-height:100%;}

【讨论】：