select trunc((to_char(sysdate, \'yyyyMMdd\') - to_char(to_date(substr(\'110101201701010016\', 7, 8), \'yyyy-MM-dd\'), \'yyyyMMdd\')) / 10000) 年龄 from dual; 执行结果: 相关文章: 2021-12-04 2021-12-04 2021-11-17 2022-12-23 2022-12-23 2021-12-04 2022-12-23 2022-12-23