/**禁止空格输入 onkeydown="return banInputSapce(event);"**/
function banInputSapce(e)
{
var keynum;
if(window.event){
keynum = e.keyCode
}else if(e.which){
keynum = e.which
}if(keynum == 32){
return false;
}
return true;
}

相关文章:

  • 2021-08-09
  • 2022-12-23
  • 2022-12-23
  • 2022-12-23
  • 2022-12-23
  • 2022-12-23
  • 2022-12-23
  • 2022-12-23
猜你喜欢
  • 2022-12-23
  • 2022-12-23
  • 2021-11-29
  • 2022-12-23
  • 2022-12-23
  • 2021-08-30
相关资源
相似解决方案