Python学习笔记 -- 列表2: 遍历:嵌套列表, 将其中同位置的元素组成新的列表

#遍历:嵌套列表, 将其中同位置的元素组成新的列表
lsts = [[1,2,3], [4,5,6],[7,8,9],[10,11,12]]

ret_x = [x for [x,y,z] in lsts]
ret_y = [y for [x,y,z] in lsts]
ret_z = [z for [x,y,z] in lsts]

print(ret_x)  #[1, 4, 7, 10]
print(ret_y)  #[2, 5, 8, 11]
print(ret_z)  #[3, 6, 9, 12]

打印结果:
[1, 4, 7, 10]
[2, 5, 8, 11]
[3, 6, 9, 12]