1、利用key排序

d = {'d1':2, 'd2':4, 'd4':1,'d3':3,}
for k in sorted(d):
    print(k,d[k])

d1 2
d2 4
d3 3
d4 1

 

2、利用value排序:__getitem__

d = {'d1':2, 'd2':4, 'd4':1,'d3':3,}
for k in sorted(d,key=d.__getitem__):
    print(k,d[k])

d4 1
d1 2
d3 3
d2 4

 

反序:reverse=True

d = {'d1':2, 'd2':4, 'd4':1,'d3':3,}
for k in sorted(d,key=d.__getitem__,reverse=True):
    print(k,d[k])

d2 4
d3 3
d1 2
d4 1

 

3、对dict_items进行排序

d = {'d1':2, 'd2':4, 'd4':1,'d3':3,}
res = sorted(d.items(),key=lambda d:d[1],reverse=True)
print(res)

 [('d2', 4), ('d3', 3), ('d1', 2), ('d4', 1)]

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