如何获取xml任意节点中某个属性值



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 1 public string GetXmlNodeValue(string strXml,string strNodeName,string strValueName)
 2     {powered by 25175.net
 3         try 
 4         {
 5             System.Xml.XmlDocument xmlDoc = new System.Xml.XmlDocument();
 6             xmlDoc.LoadXml(strXml);
 7             System.Xml.XmlNode xNode = xmlDoc.SelectSingleNode("//" + strNodeName + "");
 8             string strValue = xNode.Attributes[strValueName].Value;
 9             return strValue;
10         }
11         catch (Exception ex)
12         {
13             return ex.Message;
14         }
15         
16     }