测试 5

测试 5

思路:找规律

#include<cstdio>
#include<cstring>
#include<iostream>
#include<algorithm>
int n,m;
int main() {
    freopen("star.in","r",stdin);
    freopen("star.out","w",stdout);
    while(scanf("%d%d",&n,&m)&&n!=0&&m!=0) {
        if(!(n&1)||!(m&1)) printf("Yuri\n");
        else printf("Chito\n");
    }
    return 0;
}

测试 5

#include<set>
#include<cmath>
#include<cstdio>
#include<cstring>
#include<iostream> 
#include<algorithm>
#define mod 1000000007
using namespace std;
set<int>se;
int n,k,ans;
int val[50010],num[100000];
int cmp(int a,int b){
    return a>b;
}
int main(){
    freopen("war.in","r",stdin);
    freopen("war.out","w",stdout);
    scanf("%d%d",&n,&k);
    if(n<=100){
        int tot=0;
        memset(num,0,sizeof(num));
        for(int i=1;i<=n;i++)    scanf("%d",&val[i]);
        for(int i=1;i<=n;i++)
            for(int j=i+1;j<=n;j++)
                num[++tot]=val[i]^val[j];
        sort(num+1,num+1+tot,cmp);
        for(int i=1;i<=k;i++)    ans=(ans+num[i])%mod;
        cout<<ans;
        return 0;
    }
    if(k==1){
        for(int i=1;i<=n;i++)     scanf("%d",&val[i]);
        sort(val+1,val+1+n);
        for(int i=1;i<=n;i++)
            for(int j=i+1;j<=n;j++)
                ans=max(ans,val[i]^val[j]);
        cout<<ans;
    }
    else{
        for(int i=1;i<=n;i++){
            scanf("%d",&val[i]);
            se.insert(val[i]);
        }    
        int num1[1000],num2[1000],sum,tot1=0,tot2=0,tot=0;
        for(int i=1023;i>=1;i--){
            memset(num1,0,sizeof(num1));
            if(tot==k)    break;
            tot1=0;
            int xx=i;
            while(xx){
                num1[++tot1]=xx%2;
                xx/=2;
            }
            for(int j=1;j<=n;j++){
                memset(num2,0,sizeof(num2));
                tot2=0,sum=0;
                int yy=j;
                while(yy){
                    num2[++tot2]=yy%2;
                    yy/=2;
                }
                for(int q=1;q<=tot2;q++){
                    if(num1[q]==0&&num2[q]==1)    sum+=pow(2,q-1);
                    else if(num1[q]==1&&num2[q]==0)    sum+=pow(2,q-1); 
                }
                if(se.find(sum)!=se.end()){
                    ans=(ans+i)%mod;
                    tot++;
                    if(tot==k)    break;    
                }
            } 
        }
        cout<<ans;
    }
}
40分暴力

相关文章:

  • 2021-08-09
  • 2021-06-27
  • 2021-04-14
  • 2021-08-03
  • 2021-07-26
  • 2022-12-23
  • 2022-12-23
  • 2022-12-23
猜你喜欢
  • 2021-12-30
  • 2022-12-23
  • 2021-11-27
  • 2021-03-30
  • 2021-11-06
  • 2021-12-13
  • 2022-02-17
相关资源
相似解决方案