#include <stdio.h>

int main(void)
{
	int a[9][9]={};
	int i,j;
	for(i=0;i<9;i++){
		for(j=0;j<=i;j++){
			a[i][j] = 0;
			if(j==0 || i==j){
				a[i][j] = 1; 
			}else{
				a[i][j] = a[i-1][j-1]+a[i-1][j];
			}
			printf("%2d ",a[i][j]);
		}
		printf("\n");
	}
	
	return 0;
}

输出结果 

1
1 1
1 2 1
1 3 3 1
1 4 6 4 1
1 5 10 10 5 1
1 6 15 20 15 6 1
1 7 21 35 35 21 7 1
1 8 28 56 70 56 28 8 1

 

相关文章:

  • 2022-12-23
  • 2021-05-11
  • 2021-12-22
  • 2021-10-26
  • 2021-09-07
  • 2021-05-08
  • 2021-06-22
  • 2021-08-29
猜你喜欢
  • 2021-11-16
  • 2021-12-26
  • 2022-12-23
  • 2021-08-31
  • 2021-12-23
  • 2022-12-23
  • 2022-12-23
相关资源
相似解决方案