51nod 1183 编辑距离(dp)

题目链接：51nod 1183 编辑距离

 1 #include<cstdio>
 2 #include<cstring>
 3 #include<algorithm>
 4 using namespace std;
 5 const int N = 1001;
 6 char a[N], b[N];
 7 int dp[N][N];//dp[i][j]:a串的前i个字符转化成b串的前j个字符的最少操作数
 8 int main(){
 9     int i, j;
10     scanf("%s%s", a+1, b+1);
11     int alen = strlen(a+1);
12     int blen = strlen(b+1);
13     for(i = 0; i <= alen; ++i)
14         dp[i][0] = i;
15     for(j = 0; j <= blen; ++j)
16         dp[0][j] = j;
17     for(i = 1; i <= alen; ++i)
18         for(j = 1; j <= blen; ++j)
19             dp[i][j] = min(dp[i-1][j-1] + (a[i]!=b[j]), min(dp[i-1][j]+1, dp[i][j-1]+1));
20     printf("%d\n", dp[alen][blen]);
21     return 0;
22 }

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