We are given two strings, A and B.

shift on A consists of taking string A and moving the leftmost character to the rightmost position. For example, if A = 'abcde', then it will be 'bcdea' after one shift on A. Return True if and only if A can become B after some number of shifts on A.

Example 1:
Input: A = 'abcde', B = 'cdeab'
Output: true

Example 2:
Input: A = 'abcde', B = 'abced'
Output: false

Note:

  • A and B will have length at most 100.

 

如果把A的一部分子串移到后面,跟B相等,则返回true

 

C++(3ms):

1 class Solution {
2 public:
3     bool rotateString(string A, string B) {
4         return (A.size() == B.size() && (A+A).find(B) != string::npos) ;
5     }
6 };

 

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