cmalloc char* desStr = (char*)malloc(10);memset(desStr, '1', 9); desStr[9] ='\0';free(desStr);desStr = NULL; 相关文章: 2022-01-19 2022-12-23 2022-12-23 2022-12-23 2022-12-23 2021-11-12 2022-12-23