1. 判断偶数:number & 1 == 0 (number & 0x1)判断奇数number & 1 == 1 2.int mid = (low+high)>>1; 3.用左移(<<)右移(>>)代替乘2除2 相关文章: 2021-08-01 2022-01-22 2022-12-23 2021-10-12 2021-12-02 2022-12-23 2022-12-23 2021-07-24