Python 循环

循环
range实现循环

S = [1, 2, 3, 4, 5, 6]

for i in range(0, len(S), 2):
    print S[i]

enumerate 实现循环

S = [10, 20, 30]

for (index, value) in enumerate(S):
    print index
    print value

zip

ta = [1, 2, 3, 4]
tb = [9, 8, 7]
tc = ['a', 'b', 'c']
for (a, b, c) in zip(ta, tb, tc):
    print(a, b, c)

'''
(1, 9, 'a')
(2, 8, 'b')
(3, 7, 'c')
'''

ta = [1, 2, 3]
tb = [9, 8, 7]

# cluster
zipped = zip(ta, tb)
print(zipped)

# decompose
na, nb = zip(*zipped)
print(na, nb)
'''
[(1, 9), (2, 8), (3, 7)]
((1, 2, 3), (9, 8, 7))
'''