1 //5.公鸡5元一只,母鸡3元一只,小鸡1元3只,求100元刚好买100只鸡的可能
 2 
 3 #include<stdio.h>
 4 
 5 int main(int argc, char** argv)
 6 {
 7     int i = 0;
 8     int j = 0;
 9 
10     for (i = 0; i <= 20; i++)
11     {
12         for (j = 0; j <= 30; j++)
13         {
14             if ( (0 == ((100-i-j)%3)) && (100 == 5*i + 3*j + (100-i-j)/3))        
15                 printf("gongji:%d,muji:%d,xiaoji:%d\n", i, j, (100-i-j));
16         }
17     }
18 
19     return 0;
20 }

 

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