///查询生成交叉列表
CREATE TABLE AA
 ( AID int,
 ANAME VARCHAR(10),
 AKM VARCHAR(10)
 )

insert into AA values(1,'A','G');
insert into AA values(2,'A','R');
insert into AA values(3,'A','B');

insert into AA values(4,'B','B');
insert into AA values(5,'B','R');

insert into AA values(6,'C','R');

select * from aa

select ANAME,
max(case AKM when 'R' then 'R' else '' end)
+max(case AKM when 'G' then 'G' else '' end)
+max(case AKM when 'B' then 'B' else '' end) AKM
from aa
group by ANAME

相关文章:

  • 2021-12-27
  • 2021-09-16
  • 2021-12-11
  • 2022-12-23
  • 2022-12-23
  • 2021-09-25
猜你喜欢
  • 2022-12-23
  • 2022-12-23
  • 2022-12-23
  • 2021-12-04
  • 2022-03-03
  • 2022-12-23
  • 2022-12-23
相关资源
相似解决方案