Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 131072/131072 K (Java/Others)
Total Submission(s): 398    Accepted Submission(s): 283


2017 Multi-University Training Contest - Team 1 1001&&HDU 6033 Add More Zero【签到题,数学,水】

 

 

Sample Input
1
64
 

 

Sample Output
Case #1: 0
Case #2: 19
 

 

Source
分析:
2017 Multi-University Training Contest - Team 1 1001&&HDU 6033 Add More Zero【签到题,数学,水】

下面给出AC代码:

 1 #include <bits/stdc++.h>
 2 using namespace std;
 3 int main()
 4 {
 5     int n;
 6     int p=1;
 7     while(scanf("%d",&n)!=EOF)
 8     {
 9         int k=(n*log10(2.0));
10         printf("Case #%d: %d\n",p++,k);
11     }
12     return 0;
13 }

 

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